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14. Rank the stability of the following alkenes in order of decreasing stability: 00 II II a. I> II > III; b. III > II > I; c. I> III > II; d. II>I> III

14. Rank the stability of the following alkenes in order of decreasing stability: 00 II II a. I> II > III; b. III > II > I; c. I> III > II; d. II>I> III

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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14. Rank the stability of the following alkenes in order of decreasing stabilily: III a. I> II > III; b. III > II > I; c. I> III > II; d. II >I> III 15. Arrange the following compounds in order of increasing reactivity toward ethanol solvolysis (SN1): A: 1-butyl bromide; B: t-butyl iodide; C: isopropyl chloride; D: methyl iodide. a. B< A<C< D b. A <B<C<D c. D < C < A < B d. D<A<B<C 16. Which of the following carbocations is likely to undergo a hydride shift (rearrangement)? II III IV a. I and II; b. III; c. IV; d. II and IV 17. Arrange the following alkene in order of decreasing stability: A: (CH3)(CH3СH2)С-С(СH3)2. C: CH3CH2CH=C(CH3)2, B: CH3CH=CHCH3, D: CH2=CH2. a. A >C>B >D b. D>B>C> A c. C> A > B>D d. B> D>A> C 18. Gives the geometry assignment for the molecule below: CH CH Br a. E & E b. E & Z c. Z & Z d. Z & E 3
Transcribed Image Text:14. Rank the stability of the following alkenes in order of decreasing stabilily: III a. I> II > III; b. III > II > I; c. I> III > II; d. II >I> III 15. Arrange the following compounds in order of increasing reactivity toward ethanol solvolysis (SN1): A: 1-butyl bromide; B: t-butyl iodide; C: isopropyl chloride; D: methyl iodide. a. B< A<C< D b. A <B<C<D c. D < C < A < B d. D<A<B<C 16. Which of the following carbocations is likely to undergo a hydride shift (rearrangement)? II III IV a. I and II; b. III; c. IV; d. II and IV 17. Arrange the following alkene in order of decreasing stability: A: (CH3)(CH3СH2)С-С(СH3)2. C: CH3CH2CH=C(CH3)2, B: CH3CH=CHCH3, D: CH2=CH2. a. A >C>B >D b. D>B>C> A c. C> A > B>D d. B> D>A> C 18. Gives the geometry assignment for the molecule below: CH CH Br a. E & E b. E & Z c. Z & Z d. Z & E 3
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