14. In circle K shown below, points B, C, D, and E lie on the circle with secants HBD and HCE drawn. Prove: HE DC = HD · EB H K D 3. B.

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Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
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### Geometry Problem on Secants in a Circle

**Problem Statement:**

14. In circle \( K \) shown below, points \( B, C, D, \) and \( E \) lie on the circle with secants \( \overline{HBD} \) and \( \overline{HCE} \) drawn.

**To Prove:** 
\[ HE \cdot DC = HD \cdot EB \]

**Diagram Explanation:**

- The diagram illustrates a circle \( K \).
- Points \( B, C, D, \) and \( E \) lie on the circumference of circle \( K \).
- Two secant lines intersect at point \( H \) outside the circle, forming two secant segments: \( \overline{HBD} \) and \( \overline{HCE} \).
  - Secant \( \overline{HBD} \) intersects the circle at points \( B \) and \( D \).
  - Secant \( \overline{HCE} \) intersects the circle at points \( C \) and \( E \).

**Proof:**

We need to prove the relationship between the segments formed by the intersecting secants:
\[ HE \cdot DC = HD \cdot EB \]

This relationship can be derived using the properties of intersecting secants in a circle, specifically the secant-secant power theorem.

**Discussion Points for Students:**
1. Define secants and the secant-secant power theorem.
2. Walk through the properties of intersecting secants and how they form similar triangles.
3. Prove the relationship using geometric properties and algebraic manipulation.

Understanding these properties is key to solving problems related to circles and secants, which are common in geometry.
Transcribed Image Text:### Geometry Problem on Secants in a Circle **Problem Statement:** 14. In circle \( K \) shown below, points \( B, C, D, \) and \( E \) lie on the circle with secants \( \overline{HBD} \) and \( \overline{HCE} \) drawn. **To Prove:** \[ HE \cdot DC = HD \cdot EB \] **Diagram Explanation:** - The diagram illustrates a circle \( K \). - Points \( B, C, D, \) and \( E \) lie on the circumference of circle \( K \). - Two secant lines intersect at point \( H \) outside the circle, forming two secant segments: \( \overline{HBD} \) and \( \overline{HCE} \). - Secant \( \overline{HBD} \) intersects the circle at points \( B \) and \( D \). - Secant \( \overline{HCE} \) intersects the circle at points \( C \) and \( E \). **Proof:** We need to prove the relationship between the segments formed by the intersecting secants: \[ HE \cdot DC = HD \cdot EB \] This relationship can be derived using the properties of intersecting secants in a circle, specifically the secant-secant power theorem. **Discussion Points for Students:** 1. Define secants and the secant-secant power theorem. 2. Walk through the properties of intersecting secants and how they form similar triangles. 3. Prove the relationship using geometric properties and algebraic manipulation. Understanding these properties is key to solving problems related to circles and secants, which are common in geometry.
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