DOOD. None of the above14. If X is distributed as Binomial with n = 9 and p = 0.45, then theprobability that X is at least 0 and at most 9 isO OΟ Α. 0O B. (0.45)^9C. 1OD. (0.45)(9)15. Let A and C be independent events, with P(A) = 1/3 and P(C) = 4, thenP(AUC) isO A. 7/12O O OninedB. 1/2C. 0OD. 5/1216. Let A and C be mutually exclusive events with P(A) = 3/8, P(C) = 1/8,AU C) = ½2, then P(AC) is

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Answered: 14. If X is distributed as Binomial…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

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Problem 1P

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suppose that on each day the stock's price either moves up by $1 with probability 0.6 and down by -$1 with probablity 0.4.the changes on different days are assumed to be independent. What is the probability that the stock prices will move up at least once out of the next three consecutive days 0.7840.9360.8560.904
Suppose that a sample of peanut butter contains 0.2 insect fragments per gram. Compute the probability that the number of insect fragments in a 5-gram sample of peanut butter is each of the following values or range of values. Interpret each result. (a) Exactly three (c) At least three (e) Would it be unusual for a 5-gram sample of this supply of peanut butter to contain five or more insect fragments? (b) Fewer than three (d) At least one (a) The probability that there are exactly three insect fragments in a 5-gram sample of peanut butter is (Round to four decimal places as needed.) There will be insect fragment(s) in about of every 100 5-gram samples of peanut butter. (Round to the nearest whole number as needed.) (b) The probability that there are fewer than three insect fragments in a 5-gram sample of peanut butter is (Round to four decimal places as needed.) There will be insect fragment(s) in about of every 100 5-gram samples of peanut butter. (Round to the nearest whole number as…
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23. *An insurance policy pays an individual 100 per day for up to 3 days of hospitalization and 25 per day for each day of hospitalization thereafter. The number of days of hospitalization, X, is a discrete random variable with probability function Pr(X = k) = (1/15)(6 – k), k = 1, 2, 3, 4, 5. Calculate the expected payment for hospitalization under this policy. (213.3)
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14. If X is distributed as Binomial with n = 9 and p = 0.45, then the probability that X is at least 0 and at most 9 is