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14. For the network of Fig. 6.78, V₁ = 9 V. Determine: (a) ID- (b) Vs and Vps- (c) VG and VGS. (d) Vp. 18 V • 750 ΚΩ VG VGS '91 ΚΩ ID 2 ΚΩ VDS Vs 0.68 ΚΩ Figure 6.78 Problem 14 V=9V IDSS=8 mA

14. For the network of Fig. 6.78, V₁ = 9 V. Determine: (a) ID- (b) Vs and Vps- (c) VG and VGS. (d) Vp. 18 V • 750 ΚΩ VG VGS '91 ΚΩ ID 2 ΚΩ VDS Vs 0.68 ΚΩ Figure 6.78 Problem 14 V=9V IDSS=8 mA

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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(P4) JFET (Course: Electronic Devices and Circuit Theory).

-Use Equation Operators or write it down on paper/digital paper.

-Redraw and Apply.

-You can add //comments for a better understanding.

-Please answer without abbreviation.

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§ 6.4 Voltage-Divider Biasing 14. For the network of Fig. 6.78, VD = 9 V. Determine: (a) ID. (b) Vs and Vps- (c) VG and VGS. (d) Vp. • 750 ΚΩ m VG 18 V + VGS 91 ΚΩ ID 2 ΚΩ Vps o V₂ = 9 V 0.68 kQ2 Figure 6.78 Problem 14 IDSS = 8 mA
Transcribed Image Text:§ 6.4 Voltage-Divider Biasing 14. For the network of Fig. 6.78, VD = 9 V. Determine: (a) ID. (b) Vs and Vps- (c) VG and VGS. (d) Vp. • 750 ΚΩ m VG 18 V + VGS 91 ΚΩ ID 2 ΚΩ Vps o V₂ = 9 V 0.68 kQ2 Figure 6.78 Problem 14 IDSS = 8 mA
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