14. For each x ER let Bx = {(x, y) = R² | y ER}, notice that Bx is a subset of R². Show that B = {Bx | x ER} is a basis of a topology for IR2. What are open sets like? With the topology generated by B, does R2 satisfy the Frechet property? With the topology generated by B, is R² Hausdorff?

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