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14. Fast forward 10 years, and you are working as a dermatologist specializing on hands. You notice almost all your patients who have nail patella syndrome (N: disease; n: wild-type) are also O blood type (genotype at the ABO gene: 00). Seems like a weird coincidence, until you remember that the genes causing these two traits are linked and 10 cM apart. If someone who is N has children with someone who is NE, what is the probability they would have a kid without nail patella syndrome who is also B-blood type (genotype: BB)?

14. Fast forward 10 years, and you are working as a dermatologist specializing on hands. You notice almost all your patients who have nail patella syndrome (N: disease; n: wild-type) are also O blood type (genotype at the ABO gene: 00). Seems like a weird coincidence, until you remember that the genes causing these two traits are linked and 10 cM apart. If someone who is N has children with someone who is NE, what is the probability they would have a kid without nail patella syndrome who is also B-blood type (genotype: BB)?

Human Anatomy & Physiology (11th Edition)
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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**Transcription for Educational Website:** --- **Question 14:** Fast forward 10 years, and you are working as a dermatologist specializing in hands. You notice almost all your patients who have nail patella syndrome (N: disease; n: wild-type) are also O blood type (genotype at the ABO gene: OO). Seems like a weird coincidence, until you remember that the genes causing these two traits are linked and 10 cM apart. If someone who is \(\frac{N \, B}{n \, O}\) has children with someone who is \(\frac{N \, B}{n \, O}\), what is the probability they would have a kid without nail patella syndrome who is also B-blood type (genotype: BB)? --- **Explanation:** This problem involves understanding genetic linkage and recombination. The genes responsible for nail patella syndrome and blood type are linked, meaning they are located close to each other on the same chromosome, specifically 10 centimorgans (cM) apart. This influences their recombination frequency during meiosis, reducing the likelihood they will be inherited separately. The question asks for the probability of having a child who does not have nail patella syndrome (nn genotype) and has B blood type (BB genotype) from two parents with the \(\frac{N \, B}{n \, O}\) genotype. To solve this, consider the possible gametes produced by each parent and use the recombination frequency to calculate the probability of each relevant genetic combination.
Transcribed Image Text:**Transcription for Educational Website:** --- **Question 14:** Fast forward 10 years, and you are working as a dermatologist specializing in hands. You notice almost all your patients who have nail patella syndrome (N: disease; n: wild-type) are also O blood type (genotype at the ABO gene: OO). Seems like a weird coincidence, until you remember that the genes causing these two traits are linked and 10 cM apart. If someone who is \(\frac{N \, B}{n \, O}\) has children with someone who is \(\frac{N \, B}{n \, O}\), what is the probability they would have a kid without nail patella syndrome who is also B-blood type (genotype: BB)? --- **Explanation:** This problem involves understanding genetic linkage and recombination. The genes responsible for nail patella syndrome and blood type are linked, meaning they are located close to each other on the same chromosome, specifically 10 centimorgans (cM) apart. This influences their recombination frequency during meiosis, reducing the likelihood they will be inherited separately. The question asks for the probability of having a child who does not have nail patella syndrome (nn genotype) and has B blood type (BB genotype) from two parents with the \(\frac{N \, B}{n \, O}\) genotype. To solve this, consider the possible gametes produced by each parent and use the recombination frequency to calculate the probability of each relevant genetic combination.
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