14. Cr (BrO3)3 + Ta2(MnO4)5 → Cr2(MnO4)3 + Ta (BrO3)5 15. Nazs • 8 H2O + A → Na2S + 8 H2O = 16. Ti(CIO3)4 + A → TIC4 + O2 =

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Chapter1: Chemical Foundations
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please answer numbers 14-16, ( Balanced equation and  type of chemical reaction required for each number 

11.СH15OH + О2— Н20 + СО2 -
12.
K + 02 → K2O =
13. Тaг(MnO4)s + Al- Та + Alz(MnO-)з -
14. Cr (BrO3)з + Taz(MnO4)s — Сr2(MnOa)з + Ta (BrОз)s
15. Na2S • 8 H20 + A→ Nazs + 8 H2O =
16. Ti(CIO3)4 + A → TIC4 + 02 =
17. V2O5 + A → V + 02 =
18.Al2(CO3)з + д — Al2Oз + CO22 -
19.А(НСО3)з +д — AlbOз + CО2 + H20 %3D
20. RЫHCOЗ + Д — Rb2COз + СО2 + H2О %3D
Transcribed Image Text:11.СH15OH + О2— Н20 + СО2 - 12. K + 02 → K2O = 13. Тaг(MnO4)s + Al- Та + Alz(MnO-)з - 14. Cr (BrO3)з + Taz(MnO4)s — Сr2(MnOa)з + Ta (BrОз)s 15. Na2S • 8 H20 + A→ Nazs + 8 H2O = 16. Ti(CIO3)4 + A → TIC4 + 02 = 17. V2O5 + A → V + 02 = 18.Al2(CO3)з + д — Al2Oз + CO22 - 19.А(НСО3)з +д — AlbOз + CО2 + H20 %3D 20. RЫHCOЗ + Д — Rb2COз + СО2 + H2О %3D
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