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14. Calculate the equilibrium constant for this reaction: 2Ag* + 2Hgm 2 2Ag(s) + Hg2*2 Given: Ag* + 1e = Ag(s) E° = .80v Hg2*2 + 2e = 2Hg) E° = .79v

14. Calculate the equilibrium constant for this reaction: 2Ag* + 2Hgm 2 2Ag(s) + Hg2*2 Given: Ag* + 1e = Ag(s) E° = .80v Hg2*2 + 2e = 2Hg) E° = .79v

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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14. Calculate the equilibrium constant for this reaction: 2Ag* + 2Hg) = 2Ag(e) + Hg2*2 E° = .80v Ag* + 1e = Ag(s) Hg2*2 + 2e = 2Hg) E° = .79v Given:
Transcribed Image Text:14. Calculate the equilibrium constant for this reaction: 2Ag* + 2Hg) = 2Ag(e) + Hg2*2 E° = .80v Ag* + 1e = Ag(s) Hg2*2 + 2e = 2Hg) E° = .79v Given:
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