14. A ship travels at a bearing of 50° at 35 mph for 2 hours. It changes courseto a bearing of 130° and travels 4 hours at 30 mph. Find the distance theship is from its point of origin and its bearing from the original position.

Answered: 14. A ship travels at a bearing of 50°…

Advanced Engineering Mathematics

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ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

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14. A ship travels at a bearing of 50° at 35 mph for 2 hours. It changes course
to a bearing of 130° and travels 4 hours at 30 mph. Find the distance the
ship is from its point of origin and its bearing from the original position.

Expert Solution

Step 1

Given that first a ship travels at a bearing of 50° at 35 mph for 2 hour,

i.e the ships travels a total distance of 70 miles at a bearing of 50° .

Then the ship changes its path to a bearing of 130° an travels 4 hours at 30 mph.

i.e the ship travels a total distance of 120 miles after changing its direction to a bearing of 130°.

We get to the following diagram from the above information-

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14. A ship travels at a bearing of 50° at 35 mph for 2 hours. It changes course to a bearing of 130° and travels 4 hours at 30 mph. Find the distance the ship is from its point of origin and its bearing from the original position.