statistic bionomial distribution 14. A product output is known to be 1% defective. In a random sample of 400 components,determine the probability of includingi. 2 or less defectives,ii. 7 or more defectives.15. If 4% of the total output of panels are substandard, find the probability of obtaining 0, 1, 2,3, 4-or-more defectives in a random sample batch of 60 panels.

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Answered: 14. A product output is known to be 1%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Treatment II III 2 N = 24 G = 72 EX2 = 292 3 M = 2 M = 3 T = 16 T= 24 T= 32 SS = 16 SS = 24 SS = 20 Use an ANOVA with a = .05 to determine whether there is a significant mean difference between the two treatments. (Round to two decimal places where needed.) Source df MS Feritical Between treatments Within treatments Total F Distribution Numerator Degrees of Freedom = 6 Denominator Degrees of Freedom = 16 0.0 1.0 3.0 4.0 5.0 6.0 7.0 9.0 11.0 120 Conclusion: Fail to reject the null hypothesis; there are no significant differences among the three treatments. Reject the null hypothesis; there are no significant differences among the three treatments. Reject the null hypothesis; there are significant differences among the three treatments. o Fail to reject the null hypothesis; there are significant differences among the three treatments.
Characteristics of the Study Sample (N = 842) Sample Characteristic Frequency (N) Percentage or Mean (SD) Range Gender Female Male 408 434 48.5% 51.5% Age (years) 842 55.1 (5.3) 44–67 Race/ethnicity White, not Hispanic African American 701 141 83.3% 16.7% Smoking status Nonsmoker Currently smokes <1 pack/day Currently smokes 1+ packs/day 698 91 53 82.9% 10.8% 6.3% BMI 831 24.9 (4.1) 18.1–36.3 Which variables in the table, if any, were measured on a nominal scale? Which variables in the table, if any, were measured on an ordinal scale? Which variables in the table, if any, were measured on an interval scale? Which variables in the table, if any, were measured on a ratio scale? Which measure(s) of central tendency, if any, are presented in this table Which measure(s) of variability, if any, are presented in this table If age were normally distributed, approximately what percentage of…
Assume that when adults with smartphones are randomly selected, 61% use them in meetings or classes. If 5 adult smartphone users are randomly selected, find the probability that exactly 2 of them use their smartphones in meetings or classes. The probability is . (Round to four decimal places as needed.) Enter your answer in the answer box. Book A 20 000 00 DII DD esc F1 F2 F3 F4 F5 F6 F7 F8 F9 F10 F11 F12 ! & ) 1 2 5 7 delet { [ } ] Q W E R Y P tab + I| * 00 < CO # 3
In a random sample of 36 criminals convicted of a certain crime, it was determined that the mean length of sentencing was 53 months, with a standard deviation of 12 months. Construct and interpret a 95% confidence interval for the mean length of sentencing for this crime. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). Click here to view the table of critical t-values. Select the correct choice below and fill in the answer boxes to complete your choice. (Use ascending order. Round to one decimal place as needed.) O A. We can be 95% confident that the mean length of sentencing for the crime is between OB. There is a 95% probability that the mean length of sentencing for the crime is between OC. 95% of the sentences for the crime are between months. and and and == months. months.
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Subgroup of Participants Supine SBP Mean (SD) Standing SBP Mean (SD) Percent with > 5.0 Decrease Percent with > 5.0 Increase White women (N = 301) 120.4 (18.4) 120.0 (18.8) 32.6% 32.2% African-American women (N = 107) 122.7 (19.3) 122.8 (19.4) 30.2% 31.9% White men (N = 339) 121.2 (18.9) 120.2 (19.9) 39.5% 25.6% African-American men (N = 95) 124.7 (20.4) 125.9 (21.6) 13.7% 51.3% Total (N = 842) 121.5 (19.0) 121.1 (19.5) 29.8% 31.7% Would it be possible to analyze data in table 2 with a chi-square test? if yes, specify how
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14. A product output is known to be 1% defective. In a random sample of 400 components, determine the probability of including i. 2 or less defectives,