Why when I replace 68 N/kg with GM/r^2 in the equation GMm/r^2 = 4(PI^2)(r)/T^2 I get a different answer? The correct answer is 1.8 * 10^4 s, but I got 9.0 * 10^3 s 14. A planet of radius 7.0 ×10' m has a gravitational field strength of 68 N/kg at its surface. What is theperiod of a satellite orbiting this planet at a radius of 1.4 ×10* m (twice the planet's radius)?g-oMe , Mp- go?9-GMpGG MpmてMや

14. The free fall gravity is equal to the centripetal acceleration is, g=acg=v2r…

Answered: 14. A planet of radius 7.0 ×10' m has a…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Why when I replace 68 N/kg with GM/r^2 in the equation GMm/r^2 = 4(PI^2)(r)/T^2 I get a different answer? The correct answer is 1.8 * 10^4 s, but I got 9.0 * 10^3 s

14. A planet of radius 7.0 ×10' m has a gravitational field strength of 68 N/kg at its surface. What is the
period of a satellite orbiting this planet at a radius of 1.4 ×10* m (twice the planet's radius)?
g-oMe , Mp- go?
9-GMp
G
G Mpm
てMや

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