J 6 14. A drawdown test was conducted on a new well with results as givenbelow:Given:P₁ = 3400 psiC₁ = 18 × 10-6 psi-Tw = 0.25 ftt, hr1.503.757.5015.0037.5056.2575.00112.50150.00225.00Pwfr psi2978294929272904287628632848281027902763h = 25 ftMo = 1.8 cp$ = 12%Assuming no wellbore storage, calculate:• Average permeability• Skin factorB,Q = 300 STB/day1.1 bbl/STB=

Solution: Draw Pwf versus time in a semi log graph: Slope : m=dydx=8554.75=1.55 psi/cycle In…

14. A drawdown test was conducted on a new well with results as given below: Given: Pi = 3400 psi C₁ = 18 × 10-6 psi-1 Tw = 0.25 ft t, hr 1.50 3.75 7.50 15.00 37.50 56.25 75.00 112.50 150.00 225.00 Pwir psi 2978 2949 2927 2904 2876 2863 2848 2810 2790 2763 h = 25 ft Mo = 1.8 cp $ = 12% Assuming no wellbore storage, calculate: Average permeability • Skin factor Q = 300 STB/day B, = 1.1 bbl/STB

14. A drawdown test was conducted on a new well with results as given below: Given: Pi = 3400 psi C₁ = 18 × 10-6 psi-1 Tw = 0.25 ft t, hr 1.50 3.75 7.50 15.00 37.50 56.25 75.00 112.50 150.00 225.00 Pwir psi 2978 2949 2927 2904 2876 2863 2848 2810 2790 2763 h = 25 ft Mo = 1.8 cp $ = 12% Assuming no wellbore storage, calculate: Average permeability • Skin factor Q = 300 STB/day B, = 1.1 bbl/STB

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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