14. A chemist carries out an experiment to determine the number of moles of Cl ions in a 1 L sample of salt water. The salt water reacts with excess AgNO, solution. The resulting precipitate is collected, dried, and weighed. The mass of the AgCl precipitate is found to be 5.4 g. The chemical equation for the reaction is: AGNO,(aq) + NaCl(aq) AgCI(s) + NANO:(aq) Calculate the moles of Cl ions in the sample, and describe how the number of moles was found. Refer to the periodic table.
14. A chemist carries out an experiment to determine the number of moles of Cl ions in a 1 L sample of salt water. The salt water reacts with excess AgNO, solution. The resulting precipitate is collected, dried, and weighed. The mass of the AgCl precipitate is found to be 5.4 g. The chemical equation for the reaction is: AGNO,(aq) + NaCl(aq) AgCI(s) + NANO:(aq) Calculate the moles of Cl ions in the sample, and describe how the number of moles was found. Refer to the periodic table.
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:14. A chemist carries out an experiment to determine the number of moles of Cl ions in a 1 L sample of salt
water. The salt water reacts with excess AgNO, solution. The resulting precipitate is collected, dried,
and weighed. The mass of the AgCl precipitate is found to be 5.4 g. The chemical equation for the
reaction iş:
AgNO.(aq) + NaCl(aq) → AgCI(s) + NANO:(aq)
Calculate the moles of Cl ions in the sample, and describe how the number of moles was found. Refer
to the periodic table.
15. When iron reacts with oxygen gas, iron (II) oxide is produced. The chemical equation for the
reaction is:
4Fe + 30, 2Fe,O
Describe how to calculate and perform the calculation to determine how many grams of iron are needed
to react in excess oxygen to produce 45.5 grams of Fe,O, if the reaction has a 90% yield. Refer to the
periodic table.
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