(14) = (x – y + 5)? dx dy %3D dy (15) (x² – y²)" – xy = 0 dx dy (16) 2xy = x² + 2y² %3D dx

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter6: Applications Of The Derivative
Section6.CR: Chapter 6 Review
Problem 21CR
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Substitution Method
dy
(14) = (x – y + 5)²
dx
(15) (x² – y²) – xy = 0
(16) 2xy = x² + 2y²
-
dx
dx
Transcribed Image Text:Substitution Method dy (14) = (x – y + 5)² dx (15) (x² – y²) – xy = 0 (16) 2xy = x² + 2y² - dx dx
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