14) Write nested for loops to produce the following output: 111111 22221 3331 441 51

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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How do you do this? JAVA
**Problem Statement:**

**14)** Write nested for loops to produce the following output:

```
11111
2222
333
44
5
```

**Explanation:**

To tackle this problem, you need to use nested `for` loops. The first loop will control the rows, and the second, inner loop will handle the printing of the numbers within each row. For each row `i`, you need to print the digit `i` for `n-i+1` times, where `n` is the total number of rows, which in this case is 5.

Here's a pseudocode example to illustrate the solution:

```python
for i in range(1, 6): # Outer loop for the rows
    for j in range(6 - i): # Inner loop for the columns
        print(i, end='') # Print the digit without newline
    print() # Print a newline after each row
```

**Explanation of the Code:**

1. The outer loop (`for i in range(1, 6)`) runs from 1 to 5, representing each line number.
2. The inner loop (`for j in range(6 - i)`) runs a decreasing number of times, starting from 5 and reducing by 1 each iteration of the outer loop.
3. The `print(i, end='')` statement prints the number `i` without moving to a new line.
4. After the inner loop finishes, `print()` moves the cursor to the next line for the subsequent row.
Transcribed Image Text:**Problem Statement:** **14)** Write nested for loops to produce the following output: ``` 11111 2222 333 44 5 ``` **Explanation:** To tackle this problem, you need to use nested `for` loops. The first loop will control the rows, and the second, inner loop will handle the printing of the numbers within each row. For each row `i`, you need to print the digit `i` for `n-i+1` times, where `n` is the total number of rows, which in this case is 5. Here's a pseudocode example to illustrate the solution: ```python for i in range(1, 6): # Outer loop for the rows for j in range(6 - i): # Inner loop for the columns print(i, end='') # Print the digit without newline print() # Print a newline after each row ``` **Explanation of the Code:** 1. The outer loop (`for i in range(1, 6)`) runs from 1 to 5, representing each line number. 2. The inner loop (`for j in range(6 - i)`) runs a decreasing number of times, starting from 5 and reducing by 1 each iteration of the outer loop. 3. The `print(i, end='')` statement prints the number `i` without moving to a new line. 4. After the inner loop finishes, `print()` moves the cursor to the next line for the subsequent row.
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