14 VCw = 5 pF Cre = 12 pFCw, = 8 pF Che = 40 pFC = 8 pF5.6 k268 ka0.47 µF%230.47 uF0,82 kQB = 1203.3 ka10 k21.2 k2# 20 uF0.47 uFFigure 4a. Source VsFigure 4b. Voltage Divider Bias Amplifier4. For the network of Figures 4a and 4b:a. Determine re.b. Find Avmid = V. > Vi, without the circuit of Fig. 4a.c. Calculate Z¡.d. Determine fis, fLc, and fLe.e. Determine the low cutoff frequency fi.Does Miller Capacitance exist? Why?g. Determine fHi and fHo.h. Find fø and fr.Determine the high cutoff frequency f2.j. What is the gain-bandwidth product of the amplifier?f.i.

14 V Cw = 5 pF C = 12 pF Cw = 8 pF C= 40 pF C = 8 pF 5.6 kQ 68 ka 0.47 uF 0.82 k2 B = 120 0.47 uF 3.3 kn 10 kn 1.2 k 20 uF 0.47 µF Figure 4a. Source V: Figure 4b. Voltage Divider Bias Amplifier For the network of Figures 4a and 4b: a. Determine re. b. Find Avmid = V. > Vi, without the circuit of Fig. 4a. c. Calculate Zi. d. Determine fis, fic, and fLE. e. Determine the low cutoff frequency f1. f. Does Miller Capacitance exist? Why? g. Determine fHi and fHo. h. Find fø and fr. i. Determine the high cutoff frequency f2. j. What is the gain-bandwidth product of the amplifier?

14 V Cw = 5 pF C = 12 pF Cw = 8 pF C= 40 pF C = 8 pF 5.6 kQ 68 ka 0.47 uF 0.82 k2 B = 120 0.47 uF 3.3 kn 10 kn 1.2 k 20 uF 0.47 µF Figure 4a. Source V: Figure 4b. Voltage Divider Bias Amplifier For the network of Figures 4a and 4b: a. Determine re. b. Find Avmid = V. > Vi, without the circuit of Fig. 4a. c. Calculate Zi. d. Determine fis, fic, and fLE. e. Determine the low cutoff frequency f1. f. Does Miller Capacitance exist? Why? g. Determine fHi and fHo. h. Find fø and fr. i. Determine the high cutoff frequency f2. j. What is the gain-bandwidth product of the amplifier?

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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