show work ### Example NMR Problem**Problem Statement:**The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm?**Options:**A) 2.59 ppm B) 0.38 ppm C) 4.14 x 10^5 ppm D) 1.036 ppm E) None of the aboveTo solve this problem, you’ll need to use the formula for converting the frequency (in Hz) to parts per million (ppm):\[\text{Chemical Shift (ppm)} = \frac{\text{Shift (Hz)}}{\text{Operating Frequency (MHz)}}\]Given:- Shift = 1036 Hz- Operating Frequency = 400 MHzSubstitute these values into the formula:\[\text{Chemical Shift (ppm)} = \frac{1036}{400} = 2.59 \, \text{ppm}\]Thus, the correct answer is **A) 2.59 ppm**.

We have to predict the chemical shift in ppm.

14) The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm? A) 2.59 ppm B) 0.38 ppm C) 4.14 X10³ ppm D) 1.036 ppm E) None of above

14) The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm? A) 2.59 ppm B) 0.38 ppm C) 4.14 X10³ ppm D) 1.036 ppm E) None of above

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Mass Spectrometry

This process is an instrumental method in which a sample is changed to fast moving positive ions by electron bombardment. The charged particles vary due to their different mass to charge ratio and are estimated with the help of this difference. It is also called mass spectroscopy.

Question

show work

### Example NMR Problem

**Problem Statement:**
The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm?

**Options:**
A) 2.59 ppm
B) 0.38 ppm
C) 4.14 x 10^5 ppm
D) 1.036 ppm
E) None of the above

To solve this problem, you’ll need to use the formula for converting the frequency (in Hz) to parts per million (ppm):

\[
\text{Chemical Shift (ppm)} = \frac{\text{Shift (Hz)}}{\text{Operating Frequency (MHz)}}
\]

Given:
- Shift = 1036 Hz
- Operating Frequency = 400 MHz

Substitute these values into the formula:

\[
\text{Chemical Shift (ppm)} = \frac{1036}{400} = 2.59 \, \text{ppm}
\]

Thus, the correct answer is **A) 2.59 ppm**.

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