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14) The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm? A) 2.59 ppm B) 0.38 ppm C) 4.14 X10³ ppm D) 1.036 ppm E) None of above

14) The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm? A) 2.59 ppm B) 0.38 ppm C) 4.14 X10³ ppm D) 1.036 ppm E) None of above

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Example NMR Problem **Problem Statement:** The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm? **Options:** A) 2.59 ppm B) 0.38 ppm C) 4.14 x 10^5 ppm D) 1.036 ppm E) None of the above To solve this problem, you’ll need to use the formula for converting the frequency (in Hz) to parts per million (ppm): \[ \text{Chemical Shift (ppm)} = \frac{\text{Shift (Hz)}}{\text{Operating Frequency (MHz)}} \] Given: - Shift = 1036 Hz - Operating Frequency = 400 MHz Substitute these values into the formula: \[ \text{Chemical Shift (ppm)} = \frac{1036}{400} = 2.59 \, \text{ppm} \] Thus, the correct answer is **A) 2.59 ppm**.
Transcribed Image Text:### Example NMR Problem **Problem Statement:** The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm? **Options:** A) 2.59 ppm B) 0.38 ppm C) 4.14 x 10^5 ppm D) 1.036 ppm E) None of the above To solve this problem, you’ll need to use the formula for converting the frequency (in Hz) to parts per million (ppm): \[ \text{Chemical Shift (ppm)} = \frac{\text{Shift (Hz)}}{\text{Operating Frequency (MHz)}} \] Given: - Shift = 1036 Hz - Operating Frequency = 400 MHz Substitute these values into the formula: \[ \text{Chemical Shift (ppm)} = \frac{1036}{400} = 2.59 \, \text{ppm} \] Thus, the correct answer is **A) 2.59 ppm**.
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