14) The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm? A) 2.59 ppm B) 0.38 ppm C) 4.14 X10³ ppm D) 1.036 ppm E) None of above
14) The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm? A) 2.59 ppm B) 0.38 ppm C) 4.14 X10³ ppm D) 1.036 ppm E) None of above
Chapter13: Structure Determination: Nuclear Magnetic Resonance Spectroscopy
Section13.12: Dept 13c Nmr Spectroscopy
Problem 21P
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![### Example NMR Problem
**Problem Statement:**
The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm?
**Options:**
A) 2.59 ppm
B) 0.38 ppm
C) 4.14 x 10^5 ppm
D) 1.036 ppm
E) None of the above
To solve this problem, you’ll need to use the formula for converting the frequency (in Hz) to parts per million (ppm):
\[
\text{Chemical Shift (ppm)} = \frac{\text{Shift (Hz)}}{\text{Operating Frequency (MHz)}}
\]
Given:
- Shift = 1036 Hz
- Operating Frequency = 400 MHz
Substitute these values into the formula:
\[
\text{Chemical Shift (ppm)} = \frac{1036}{400} = 2.59 \, \text{ppm}
\]
Thus, the correct answer is **A) 2.59 ppm**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb987d8c1-664b-448b-b573-1ab7f66094f6%2F3cca0ed6-10b6-48bb-8acd-c4d38d4aa039%2F5d94yf3_processed.png&w=3840&q=75)
Transcribed Image Text:### Example NMR Problem
**Problem Statement:**
The chemical shift for benzylic protons in ethylbenzene is 1036 Hz in a 400 MHz NMR. What is the chemical shift for the benzylic protons in ppm?
**Options:**
A) 2.59 ppm
B) 0.38 ppm
C) 4.14 x 10^5 ppm
D) 1.036 ppm
E) None of the above
To solve this problem, you’ll need to use the formula for converting the frequency (in Hz) to parts per million (ppm):
\[
\text{Chemical Shift (ppm)} = \frac{\text{Shift (Hz)}}{\text{Operating Frequency (MHz)}}
\]
Given:
- Shift = 1036 Hz
- Operating Frequency = 400 MHz
Substitute these values into the formula:
\[
\text{Chemical Shift (ppm)} = \frac{1036}{400} = 2.59 \, \text{ppm}
\]
Thus, the correct answer is **A) 2.59 ppm**.
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