Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
(13%) Problem 6: A hollow non-conducting spherical shell has inner radius R₂ = 7 cm and outer radius R₂ = 19 cm. A charge Q = -35 nC lies at the center of the shell. The shell carries a spherically symmetric charge density o = Ar for R₁

(13%) Problem 6: A hollow non-conducting spherical shell has inner radius R₂ = 7 cm and outer radius R₂ = 19 cm. A charge Q = -35 nC lies at the center of the shell. The shell carries a spherically symmetric charge density o = Ar for R₁

icon
Related questions
Question

Please help with 3 and 4

(13%) Problem 6: A hollow non-conducting spherical shell has inner radius R, = 7 cm and outer radius R₂ = 19 cm. A charge Q = -35 nC lies at the center of the shell. The shell carries a spherically symmetric charge density g = Ar for R₁ <r < R₂ that increases linearly with radius, where A = 24 µC/m4. R₂ ✓ 25% Part (a)_ Write an equation for the radial electric field in the region r < R₁ in terms of Q,r, and Coulomb's constant k. You may take the positive direction as outward. select part Er < R₁ = (kQ)/r² ✓ Correct! ✓ 25% Part (b) What is the radial electric field at the point r = 0.5R₁? Given your answer in units of kN/C, and take the positive direction outwards. E(0.5R₂) = -257 E(0.5R₂) = -257 ✓ Correct! 25% Part (c) What is the radial electric field at the point r = 0.5(R/+R₂)? Give your answer in units of kN/C. E(0.5(R1+R₂)) = 10.32 E(0.5(R₁+R₂)) = -10.32 X Attempts Remain ▷ A 25% Part (d) What is the radial electric field at the point r = 2R₂? Give your answer in units of kN/C.
Transcribed Image Text:(13%) Problem 6: A hollow non-conducting spherical shell has inner radius R, = 7 cm and outer radius R₂ = 19 cm. A charge Q = -35 nC lies at the center of the shell. The shell carries a spherically symmetric charge density g = Ar for R₁ <r < R₂ that increases linearly with radius, where A = 24 µC/m4. R₂ ✓ 25% Part (a)_ Write an equation for the radial electric field in the region r < R₁ in terms of Q,r, and Coulomb's constant k. You may take the positive direction as outward. select part Er < R₁ = (kQ)/r² ✓ Correct! ✓ 25% Part (b) What is the radial electric field at the point r = 0.5R₁? Given your answer in units of kN/C, and take the positive direction outwards. E(0.5R₂) = -257 E(0.5R₂) = -257 ✓ Correct! 25% Part (c) What is the radial electric field at the point r = 0.5(R/+R₂)? Give your answer in units of kN/C. E(0.5(R1+R₂)) = 10.32 E(0.5(R₁+R₂)) = -10.32 X Attempts Remain ▷ A 25% Part (d) What is the radial electric field at the point r = 2R₂? Give your answer in units of kN/C.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 4 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer