132 Chapter 1 Equations and Inequalities 43. (2x + 1)2 = 27 44. (5y + 2)? - 48 = 0 77. 3x2 = - 5x 1 78. 2x = 5x + 11 45. (5x + 1)2 = -8 46. (7y + 2)2 + 48 = 0 79. x + 1 = -7x 80. 13x + 1 = -10x 81. 3x + 6x = -1 82. 2x(x + 3) = -1 Complete the square to make each a perfect-square trinomial. 47. x2 + 6x 48. x? + 8x 83. 7x = 2x + 2 84. 5x x + = 3 49. x - 4x 50. x – 12x 85. x + 2x + 2 = 0 86. a + 4a + 8 = 0 51. a + 5a 52. 12 + 9t 87. y + 4y + 5 = 0 88. x² + 2x + 5 = 0 53. 7 - 11r 54. s? - 7s 89. x2 - 2x = -5 90. z2 – 3z = -8 3 55. y + 3 56. p + p 2 2 x%3D 9 5 91. x - 92. x + = X 1 57. q - 2 58. m - " 59 Solve each formula for the indicated variable. 1 93. h = 28 Solve each equation by completing the square. 94. x² + y? = r; x 59. x + 12x = -8 60. x - 6x = -1 61. x - 10x + 37 = 0 62. a + 16a + 82 = 0 95. h = 641 – 161; t 96. y = 16x - 4; x 63. x² + 5 = -5x 64. x2 + 1 = -4x = 1; x b? 97. 98. 1; y b²
132 Chapter 1 Equations and Inequalities 43. (2x + 1)2 = 27 44. (5y + 2)? - 48 = 0 77. 3x2 = - 5x 1 78. 2x = 5x + 11 45. (5x + 1)2 = -8 46. (7y + 2)2 + 48 = 0 79. x + 1 = -7x 80. 13x + 1 = -10x 81. 3x + 6x = -1 82. 2x(x + 3) = -1 Complete the square to make each a perfect-square trinomial. 47. x2 + 6x 48. x? + 8x 83. 7x = 2x + 2 84. 5x x + = 3 49. x - 4x 50. x – 12x 85. x + 2x + 2 = 0 86. a + 4a + 8 = 0 51. a + 5a 52. 12 + 9t 87. y + 4y + 5 = 0 88. x² + 2x + 5 = 0 53. 7 - 11r 54. s? - 7s 89. x2 - 2x = -5 90. z2 – 3z = -8 3 55. y + 3 56. p + p 2 2 x%3D 9 5 91. x - 92. x + = X 1 57. q - 2 58. m - " 59 Solve each formula for the indicated variable. 1 93. h = 28 Solve each equation by completing the square. 94. x² + y? = r; x 59. x + 12x = -8 60. x - 6x = -1 61. x - 10x + 37 = 0 62. a + 16a + 82 = 0 95. h = 641 – 161; t 96. y = 16x - 4; x 63. x² + 5 = -5x 64. x2 + 1 = -4x = 1; x b? 97. 98. 1; y b²
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
For number 95, how did they get an 8?
![146 of 898
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Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time
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132 Chapter 1 Equations and Inequalities
43. (2x + 1)² = 27
44. (5y + 2)² – 48 = 0
77. 3x2 = - 5x – 1
78. 2x2 = 5x + 11
45. (5x + 1)² = -8
46. (7y + 2)² + 48 = 0
79. x² + 1 = -7x
80. 13x2 + 1 = - 10x
81. 3x + 6x = - 1
82. 2x(x + 3) = –1
Complete the square to make each a perfect-square
trinomial.
47. x² + 6x
48. x² + 8x
83. 7x = 2x + 2
84. 5x x +
= 3
49. х2 — 4х
50. х2
12x
85. x + 2x + 2 = 0
86. a? + 4a + 8 = 0
51. a + 5a
52. 12 + 9t
87. y + 4y + 5 = 0
88. x² + 2x + 5 = 0
53. 2 — 11г
54. s² – 7.s
89. x2 – 2x = - 5
90. z2 – 3z = -8
3
55. y +
3
56. р? +
2
91. x² -
3
2
92. x? +
4
1
57. q - 34
2
58. т?
m
Solve each formula for the indicated variable.
Solve each equation by completing the square.
1
93. h =
94. x² + y? = r²; x
59. x + 12x = -8
60. x² – 6x = -1
61. х.
10x + 37 = 0
62. a + 16a + 82 = 0
95. h = 64t – 167²; t
96. у %3
16x2 – 4; x
63. x² + 5 = -5x
64. x² + 1 = -4x
97.
1; у
98.
a
= 1; x
%3D
65. y + 11y = -49
66. x² – 5x = -22
99.
a?
1; а
100.
a?
1; b
b²
67. 2x2 – 20x = -49
68. 4x2 + 8x = 7
69. 3x² = 1 – 4x
70. 3x2 + 4x = 5
101. х2 + ху — у? %3D 0;B х
71. 2x² = 3x + 1
72. 2x2 + 5x = 14
102. х? — 3ху + у' %3D0; у
Use the discriminant to determine the number and type of
roots. Do not solve the equation.
Use the Quadratic Formula to solve each equation.
74. 7z2 = –14z – 13
103. x + 6x + 9 = 0
104. -3x2 + 2x = 21
73. 9х?
18x – 14
105. 3x2 – 2x + 5 = 0
106. 9x² + 42.x + 49 = 0
75. 2x2 = 14x –
30i
76. 5x² + x = -5
Copyright 2017 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).
Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right
o remove additional content at any time if subsequent rights restrictions require it.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd979954b-f745-411c-bdb6-7a29d0236fd1%2F46298a46-d053-4e6c-b11b-e5d4c9445fc5%2Fr1ptle_processed.jpeg&w=3840&q=75)
Transcribed Image Text:146 of 898
Copyright 2017 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).
Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right to remove additional content at any time
subsequent rights restrictions require it.
132 Chapter 1 Equations and Inequalities
43. (2x + 1)² = 27
44. (5y + 2)² – 48 = 0
77. 3x2 = - 5x – 1
78. 2x2 = 5x + 11
45. (5x + 1)² = -8
46. (7y + 2)² + 48 = 0
79. x² + 1 = -7x
80. 13x2 + 1 = - 10x
81. 3x + 6x = - 1
82. 2x(x + 3) = –1
Complete the square to make each a perfect-square
trinomial.
47. x² + 6x
48. x² + 8x
83. 7x = 2x + 2
84. 5x x +
= 3
49. х2 — 4х
50. х2
12x
85. x + 2x + 2 = 0
86. a? + 4a + 8 = 0
51. a + 5a
52. 12 + 9t
87. y + 4y + 5 = 0
88. x² + 2x + 5 = 0
53. 2 — 11г
54. s² – 7.s
89. x2 – 2x = - 5
90. z2 – 3z = -8
3
55. y +
3
56. р? +
2
91. x² -
3
2
92. x? +
4
1
57. q - 34
2
58. т?
m
Solve each formula for the indicated variable.
Solve each equation by completing the square.
1
93. h =
94. x² + y? = r²; x
59. x + 12x = -8
60. x² – 6x = -1
61. х.
10x + 37 = 0
62. a + 16a + 82 = 0
95. h = 64t – 167²; t
96. у %3
16x2 – 4; x
63. x² + 5 = -5x
64. x² + 1 = -4x
97.
1; у
98.
a
= 1; x
%3D
65. y + 11y = -49
66. x² – 5x = -22
99.
a?
1; а
100.
a?
1; b
b²
67. 2x2 – 20x = -49
68. 4x2 + 8x = 7
69. 3x² = 1 – 4x
70. 3x2 + 4x = 5
101. х2 + ху — у? %3D 0;B х
71. 2x² = 3x + 1
72. 2x2 + 5x = 14
102. х? — 3ху + у' %3D0; у
Use the discriminant to determine the number and type of
roots. Do not solve the equation.
Use the Quadratic Formula to solve each equation.
74. 7z2 = –14z – 13
103. x + 6x + 9 = 0
104. -3x2 + 2x = 21
73. 9х?
18x – 14
105. 3x2 – 2x + 5 = 0
106. 9x² + 42.x + 49 = 0
75. 2x2 = 14x –
30i
76. 5x² + x = -5
Copyright 2017 Cengage Learning. All Rights Reserved. May not be copied, scanned, or duplicated, in whole or in part. Due to electronic rights, some third party content may be suppressed from the eBook and/or eChapter(s).
Editorial review has deemed that any suppressed content does not materially affect the overall learning experience. Cengage Learning reserves the right
o remove additional content at any time if subsequent rights restrictions require it.
![6:04 PM Sun Mar 20
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AA
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Secondary Pr...
Free Chart -...
www.astro.c...
The formula...
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Expert Solution & Answer
Answer to Problem 95E
8±/64–h
The formula for t is t =
4
Explanation of Solution
Quadratic Formula:
-b±/b² -4ac
The solutions of the general quadratic equation, ax? + bx + c = 0, are x =
(a + 0).
2a
Calculation:
The given equation can be rewritten as 1612 – 64t + h = 0.
Solve 16t2 – 64t + h = 0 for t by using Quadratic formula as follows.
Here, a =
= 16, b
= -64 and c = h.
Substitute these values in the Quadratic Formula as,
-b ± /b? – 4ac
t =
2a
- (-64) ±
(-64)² – 4 (16) (h)
2 (16)
64 + V-64h + 4096
How?
2 (16)
64
8-h + 64
32
8 ± V64 – h
8±/64-h
Therefore, the formula for t is t =
Final statement:
8±/64-h
The formula for t is t =
4
< Previous
Next >
Chapter 1.4, Problem 94E
Chapter 1.4, Problem 96E
||
||
||](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd979954b-f745-411c-bdb6-7a29d0236fd1%2F46298a46-d053-4e6c-b11b-e5d4c9445fc5%2Ftf2juyj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6:04 PM Sun Mar 20
74%
AA
A bartleby.com
Secondary Pr...
Free Chart -...
www.astro.c...
The formula...
b Answered: 59...
TINY Tigers Eye M...
Q SEARCH
& ASK AN EXPERT
CHAT
VX MATH SOLVER
Expert Solution & Answer
Answer to Problem 95E
8±/64–h
The formula for t is t =
4
Explanation of Solution
Quadratic Formula:
-b±/b² -4ac
The solutions of the general quadratic equation, ax? + bx + c = 0, are x =
(a + 0).
2a
Calculation:
The given equation can be rewritten as 1612 – 64t + h = 0.
Solve 16t2 – 64t + h = 0 for t by using Quadratic formula as follows.
Here, a =
= 16, b
= -64 and c = h.
Substitute these values in the Quadratic Formula as,
-b ± /b? – 4ac
t =
2a
- (-64) ±
(-64)² – 4 (16) (h)
2 (16)
64 + V-64h + 4096
How?
2 (16)
64
8-h + 64
32
8 ± V64 – h
8±/64-h
Therefore, the formula for t is t =
Final statement:
8±/64-h
The formula for t is t =
4
< Previous
Next >
Chapter 1.4, Problem 94E
Chapter 1.4, Problem 96E
||
||
||
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