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13-1II. A 0.2-kg spool slides down along a smooth rod. If the rod has a constant angular rate of rotation = 2 rad/s in the vertical plane, show that the equations of motion for the spool are i – 4r – 9.81 sin 0 = 0 and 0.8i + N, - 1.962 cos 0 = 0, where N, is the magnitude of the normal force of the rod on the spool. Using the methods of differential equations, it can be shown that the solution of the first of these equations is r = Cje " + Cze – (9.81/8) sin 2t. If r, i, and 0 are zero when i = 0, evaluate the constants C, and C, determine r at the instant 0 = 7/4 rad. %3D -21 e = 2 rad/s

13-1II. A 0.2-kg spool slides down along a smooth rod. If the rod has a constant angular rate of rotation = 2 rad/s in the vertical plane, show that the equations of motion for the spool are i – 4r – 9.81 sin 0 = 0 and 0.8i + N, - 1.962 cos 0 = 0, where N, is the magnitude of the normal force of the rod on the spool. Using the methods of differential equations, it can be shown that the solution of the first of these equations is r = Cje " + Cze – (9.81/8) sin 2t. If r, i, and 0 are zero when i = 0, evaluate the constants C, and C, determine r at the instant 0 = 7/4 rad. %3D -21 e = 2 rad/s

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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13-1II. A 0.2-kg spool slides down along a smooth rod. If the rod has a constant angular rate of rotation = 2 rad/s in the vertical plane, show that the equations of motion for the spool are i – 4r – 9.81 sin 0 = 0 and 0.8i + N, - 1.962 cos 0 = 0, where N, is the magnitude of the normal force of the rod on the spool. Using the methods of differential equations, it can be shown that the solution of the first of these equations is r = Cje " + Cze – (9.81/8) sin 2t. If r, i, and 0 are zero when i = 0, evaluate the constants C, and C, determine r at the instant 0 = 7/4 rad. %3D -21 e = 2 rad/s
Transcribed Image Text:13-1II. A 0.2-kg spool slides down along a smooth rod. If the rod has a constant angular rate of rotation = 2 rad/s in the vertical plane, show that the equations of motion for the spool are i – 4r – 9.81 sin 0 = 0 and 0.8i + N, - 1.962 cos 0 = 0, where N, is the magnitude of the normal force of the rod on the spool. Using the methods of differential equations, it can be shown that the solution of the first of these equations is r = Cje " + Cze – (9.81/8) sin 2t. If r, i, and 0 are zero when i = 0, evaluate the constants C, and C, determine r at the instant 0 = 7/4 rad. %3D -21 e = 2 rad/s
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