Source13.8 kVEine 13.8 kV=lline = 5.312 AEphase(source) = 7.967 kVIphase(source) = 5.312 AEphase (load) = 7.967 kVIphase(load) = 5.312 APtotal= 126.96 kWLoadM1.5 k

Given data, Circuit diagram is given as,

Answered: 13.8 kV Source Load m 1.5KG

Engineering

Electrical Engineering

13.8 kV Source Load m 1.5KG

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter7: Alternating Current, Power Distribution, And Voltage Systems

Section: Chapter Questions

Problem 16RQ

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Concept explainers

KVL and KCL

KVL stands for Kirchhoff voltage law. KVL states that the total voltage drops around the loop in any closed electric circuit is equal to the sum of total voltage drop in the same closed loop.

Sign Convention

Science and technology incorporate some ideas and techniques of their own to understand a system skilfully and easily. These techniques are called conventions. For example: Sign conventions of mirrors are used to understand the phenomenon of reflection and refraction in an easier way.

Question

Source
13.8 kV
Eine 13.8 kV
=
lline = 5.312 A
Ephase(source) = 7.967 kV
Iphase(source) = 5.312 A
Ephase (load) = 7.967 kV
Iphase(load) = 5.312 A
Ptotal= 126.96 kW
Load
M
1.5 k

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