13.4) In the previous problem, you drew the predominant form of leucine at pH= 1.0, pH = 7.4, and pH = 12.0. These structures are shown below. What is the total charge of leucine at pH = 1.0, pH = 7.4, and pH = 12.0? H pH = 1.0 H H H-Nc−c-0–H :0: CH₂ CHCH3 CH3 total charge = 1+ There is a formal charge of 1+ on the nitrogen. physiological pH (pH = 7.4) H H :0: | H-N CICIO: H CH₂ CHCH3 CH3 total charge=0 There is a formal charge of 1+ on the nitrogen, and a formal charge of 1- on the oxygen. Adding these charges give a total charge = 0. H- pH = 12.0 H :0: || C-C H CH₂ CHCH3 CH3 total charge = 1- There is a formal charge of 1- on the oxygen.
13.4) In the previous problem, you drew the predominant form of leucine at pH= 1.0, pH = 7.4, and pH = 12.0. These structures are shown below. What is the total charge of leucine at pH = 1.0, pH = 7.4, and pH = 12.0? H pH = 1.0 H H H-Nc−c-0–H :0: CH₂ CHCH3 CH3 total charge = 1+ There is a formal charge of 1+ on the nitrogen. physiological pH (pH = 7.4) H H :0: | H-N CICIO: H CH₂ CHCH3 CH3 total charge=0 There is a formal charge of 1+ on the nitrogen, and a formal charge of 1- on the oxygen. Adding these charges give a total charge = 0. H- pH = 12.0 H :0: || C-C H CH₂ CHCH3 CH3 total charge = 1- There is a formal charge of 1- on the oxygen.
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
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Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:13.4) In the previous problem, you drew the predominant form of leucine at pH = 1.0, pH = 7.4, and pH = 12.0. These structures
are shown below. What is the total charge of leucine at pH = 1.0, pH = 7.4, and pH = 12.0?
H
H-N
H
pH = 1.0
H :0:
I ||
с
CH₂
|
CHCH3
-Ö-H
CH3
total charge = 1+
There is a formal charge of 1+ on the
nitrogen.
physiological pH (pH = 7.4)
H
H :0:
1
||
-C-0:
H-
|
H
CH₂
|
CHCH3
|
CH3
total charge = 0
There is a formal charge of 1+ on the
nitrogen, and a formal charge of 1- on
the oxygen. Adding these charges give
a total charge = 0.
pH = 12.0
H
|
H-N-
:0:
||
H
CH₂
|
CHCH3
T
CH3
total charge = 1-
There is a formal charge of 1- on the
oxygen.
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