13.2 鄭28

Q: 2- Determine the highest positive real root of x' - 6x² +1lx = 6.1 Using Secant method (perform 2…

A: Let, f(x)=x3-6x2+11x-6.1=0 is the given equation. here lower guess = 2.5 and upper guess = 3.5. We…

Q: 15 estimate, root of fa) =x²-7.

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Q: Find all absolute maxima and minima values for the function y=x^2+(54/x), on the intervial [1,108]

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Q: What is the intergral of 1/sqrt((1+t2)) dt

A: we have to find the integral :-I = ∫11+t2 dtnow for solving integral , put t = tanu⇒dt = sec2u du…

Q: If M= (16x^8y^-4)^1/4 / 32x^-2y^8, determine values for x and y so that a) M=1, b) M<O

A: The objective of the question is to find the values of x and y that satisfy the given equation under…

Q: – (In x)" = 0 –1

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Q: Use Fixed-Point Iteration Method to obtain a real root of x^3-5x+1=0 with x₀=0 until absolute error

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Q: find the roots using secant method. Stop until at 15th iteration or when approximate percent…

A: The secant method is xn=xn-1-fxn-1xn-1-xn-2fxn-1-fxn-2. The function is fx=2x4+13x3+29x2+27x+9 Set…

Q: Find the roots of x^2 + (k^2+1/k) x + 1 = 0

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Q: Integrate sqrt (16+x^2) from 0 to 4

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Q: Find the root using Regula Falsi Method (show your table) x^2-6x+9=0   Ans. x=3

A: Regula falsi method or false position is a numerical method to solve equations in one unknown. This…

Q: Use the approximation (1+x)k ~~1 +kx to estimate (1.0004)19 and 7^square root of 1.005.

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Q: Find the rod of greatest length that can be inserted between y= square root of x and y=x^3…

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Q: Use bisection method to find the root of x^3 –x^2 – 3x – 3 with two initial points xl=3 and xr=2 and…

A: The given equation is x3-x2-3x-3=0. To find: the root between 2 and 3 .

Q: QI/ Prove that the equation x (Inx)* has a root in the interval [4,5].Then by bisecting this…

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Q: Use bisection method to find the maximum of log(x)/(1+x^2).

A: It is given that

Q: The function defined by ?(?)=3x^2−5x−2 changes sign in the interval [1, 3]. Use seven iterations of…

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Q: Find the root of the equation by using the method of newton rephson x^3-3x^2+Ssin(x)=0

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