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13.17 Predict the multiplicity of the signal indicated below in its 1H-NMR spectrum. CI

13.17 Predict the multiplicity of the signal indicated below in its 1H-NMR spectrum. CI

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Give the splitting pattern expected for the indicated H-NMR signal.

### Text: **13.17 Predict the multiplicity of the signal indicated below in its 1H-NMR spectrum.** ### Diagram Description: The diagram shows a molecular structure of a compound. The molecule is a cyclic ester (lactone) with an embedded six-membered ring containing one oxygen atom and one chlorine atom. Key features: - The ring includes an oxygen atom double-bonded to one carbon (part of a carbonyl group). - A chlorine atom is attached to another carbon in the ring. - An arrow is pointing to a specific hydrogen atom (indicated by the blue arrow) on the carbon adjacent to the carbon with the chlorine atom. ### Explanation: To predict the multiplicity of the indicated hydrogen's signal in the 1H-NMR spectrum, consider the following: - **Multiplicity** is determined by the number of hydrogens on adjacent carbons, according to the n+1 rule, where n is the number of neighboring hydrogens. - The closest neighboring carbon to the hydrogen pointed by the arrow has one hydrogen (because it is adjacent to the carbon with the chlorine atom). - Therefore, the multiplicity of the signal for this hydrogen is a **doublet** (n+1 = 1+1 = 2) since it has one neighboring hydrogen.
Transcribed Image Text:### Text: **13.17 Predict the multiplicity of the signal indicated below in its 1H-NMR spectrum.** ### Diagram Description: The diagram shows a molecular structure of a compound. The molecule is a cyclic ester (lactone) with an embedded six-membered ring containing one oxygen atom and one chlorine atom. Key features: - The ring includes an oxygen atom double-bonded to one carbon (part of a carbonyl group). - A chlorine atom is attached to another carbon in the ring. - An arrow is pointing to a specific hydrogen atom (indicated by the blue arrow) on the carbon adjacent to the carbon with the chlorine atom. ### Explanation: To predict the multiplicity of the indicated hydrogen's signal in the 1H-NMR spectrum, consider the following: - **Multiplicity** is determined by the number of hydrogens on adjacent carbons, according to the n+1 rule, where n is the number of neighboring hydrogens. - The closest neighboring carbon to the hydrogen pointed by the arrow has one hydrogen (because it is adjacent to the carbon with the chlorine atom). - Therefore, the multiplicity of the signal for this hydrogen is a **doublet** (n+1 = 1+1 = 2) since it has one neighboring hydrogen.
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