13. nts) Rearrange the following lines of code to produce code that moves the first zero of an array to the end. For example, if the array contains 1 2 3 0 4 05 6 then afterwards the array will contain 1 2 3 4 0 5 6 G All lines are used. The variable len contains the length of the array. Segment in the Correct Order Segment NOT IN THE CORRECT ORDER int pos = 0; //don't move this values[i 1] values [i]; bool found this false; //don't move if (values [pos] true; } %3D 0) { found %3D while (pos < len && !found) for (int i = pos + 1; i < len; i++) if (found) { values[len 1] = 0; } else { pos++ } {

C++ for Engineers and Scientists
4th Edition
ISBN:9781133187844
Author:Bronson, Gary J.
Publisher:Bronson, Gary J.
Chapter7: Arrays
Section7.3: Declaring And Processing Two-dimensional Arrays
Problem 7E: (Electrical eng.) a. An engineer has constructed a two-dimensional array of real numbers with three...
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A.
|三三
Calibri
12
BIU
13. nts) Rearrange the following lines of code to produce code that moves the first zero of an array to
the end. For example, if the array contains 1 2 30 4 0 5 6 then afterwards the array will contain 1 2
3 4 0 5 6 G All lines are used. The variable len contains the length of the array.
Segment in the Correct Order
Segment NOT IN THE CORRECT ORDER
int pos
0; //don't move this
values[i
1]
values [i];
bool found
this
false; //don't move
if (values[pos]
true; }
0) { found
while (pos < len && !found)
for (int i
pos + 1; i < len; i++)
%3D
if (found) { values[len - 1]
= 0; }
else { pos++ }
Transcribed Image Text:A. |三三 Calibri 12 BIU 13. nts) Rearrange the following lines of code to produce code that moves the first zero of an array to the end. For example, if the array contains 1 2 30 4 0 5 6 then afterwards the array will contain 1 2 3 4 0 5 6 G All lines are used. The variable len contains the length of the array. Segment in the Correct Order Segment NOT IN THE CORRECT ORDER int pos 0; //don't move this values[i 1] values [i]; bool found this false; //don't move if (values[pos] true; } 0) { found while (pos < len && !found) for (int i pos + 1; i < len; i++) %3D if (found) { values[len - 1] = 0; } else { pos++ }
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