What’s the answer to question 13 and 14? ab | S xS Gravity in Space WS | Schoology xK 2.5 Gravity in Space.docM Inbox (2,392)- 2023davisidalisr xeb.kamihq.com/web/viewer.html?file=https%3A%2F%2Faaps.schoology.com%2Fattachment%2F1744295819%2Fsource%2Fe5b65ac588CA My Drive 2.5 Gravity in Space.doc100%13. If Peto the ship. What force would the jetpack have to exert to give Pete an acceleration of 5m/s??tumbled off the ship during his spacewalk, he would be able to use his jetpack to returnSHOW YOUR EQUATION & WORK!14. Pete finally returns safely to Earth. He goes out for dinner with his girlfriend Petra. Petra'smass is 500 kg. Do Pete and Petra experience the same force of gravity? Do they experiencethe same acceleration due to gravity?Reference1 pound = 0.45 kgW = mgg = 9.8 m/s?F = maa = F/mm = FlaEE Physics In Space! Newton's Laws In ActionPete the Polar Bear weighs 1,434 pounds on Earth.Planet or MoonEarthLuna1.6 m/s2MarsJupiter23.6 m/s?Saturn10.1 m/s2Acceleration Due to Gravity9.8 m/s23.8 m/s?

As mass of Pete is 1434 pounds therefore his mass in kg M=1434 lb×0.45 kg/lbM=645.3 kg

13. If Pete tumbled off the ship during his spacewalk, he would be able to use his jetpack to return to the ship. What force would the jetpack have to exert to give Pete an acceleration of 5 m/s?? SHOW YOUR EQUATION & WORK! 14. Pete finally returns safely to Earth. He goes out for dinner with his girlfriend Petra. Petra's mass is 500 kg. Do Pete and Petra experience the same force of gravity? Do they experience the same acceleration due to gravity?

13. If Pete tumbled off the ship during his spacewalk, he would be able to use his jetpack to return to the ship. What force would the jetpack have to exert to give Pete an acceleration of 5 m/s?? SHOW YOUR EQUATION & WORK! 14. Pete finally returns safely to Earth. He goes out for dinner with his girlfriend Petra. Petra's mass is 500 kg. Do Pete and Petra experience the same force of gravity? Do they experience the same acceleration due to gravity?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

An airplane needs to head due north, but there is a wind blowing from the southwest at 80 km/hr. The plane flies with an airspeed of 890 km/hr. To end up flying due north, how many degrees west of north will the pilot need to fly the plane? (Round your answer to three decimal places.)
Suppose you walk 12.5 m in a direction exactly 19° south of west then you walk 20.5 m in a direction exactly 42° west of north. How far are you from your starting point, in meters? What is the angle of the compass direction of a line connecting your starting point to your final position measured North of West in degrees?
The sun has a radius of 432,000 miles, and its center is 93,000,000 miles from the center of Earth. Let v and w be the vectors illustrated in the figure. (a) Express v and w in i, j form. (b) Approximate the angle between v and w.
You walk 20m 40 degrees south of west, then walk 12m 20 degrees east of south, how many degrees south of west is the line representing displacement?
Which of the following statements are true of the quantity mass? The standard English unit of mass the slug The mass of an object can be measured in pounds The mass of an object is variable and dependent upon its location The mass of an object is dependent upon the value of the acceleration of gravity
How do scientists define length in terms of meters?
Give the names of two length units that are longer than a metre. What is their connection to the metre?
You are driving 52 mi/h and take your eyes off the road for "just a second" (exactly one second). What distance (in feet) do you travel in this time?
Longest to shortest length 10 yards 1 km 50 in 1*10^4 cm
A student measured the side length of a cube and found it to be 1 = (3.3 + 0.1) cm. The volume (V = 1³) of the cube with its error is (V + U(V)) (Please show me the calculations in details) a) 35.9 ± 0.3 cm³ b) 35.9 +3.3 cm³ c) 35.9 +0.3 m³ d) 35.9 +3.3 m³