13. If an ad for a computer describes a memory having 4 x 23º bytes, how many gigabytes of the computer are uniquely addressable?

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
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**Question 13:**   
If an ad for a computer describes a memory having \( 4 \times 2^{30} \) bytes, how many gigabytes of the computer are uniquely addressable?

- **A.** 4GB  
- **B.** 8GB  
- **C.** 16GB  
- **D.** 4MB  
- **E.** 8MB  

**Explanation:**  
This question tests your understanding of binary storage and addressing in computers. The expression \( 2^{30} \) represents one gigabyte (GB) since it equates to 1,073,741,824 bytes. Therefore, \( 4 \times 2^{30} \) bytes are equal to 4 gigabytes. The correct answer is **A. 4GB**.
Transcribed Image Text:**Question 13:** If an ad for a computer describes a memory having \( 4 \times 2^{30} \) bytes, how many gigabytes of the computer are uniquely addressable? - **A.** 4GB - **B.** 8GB - **C.** 16GB - **D.** 4MB - **E.** 8MB **Explanation:** This question tests your understanding of binary storage and addressing in computers. The expression \( 2^{30} \) represents one gigabyte (GB) since it equates to 1,073,741,824 bytes. Therefore, \( 4 \times 2^{30} \) bytes are equal to 4 gigabytes. The correct answer is **A. 4GB**.
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