13. Determine the molality of a 3.050 M solution of NaCl at 25o C, given that the density of the solution is 1.11401 g/mL at this temperature.         A) 3.259 m B) 3.050 m C) 2.934 m D) 2.738 m E) 0.1600 m Part B) What is the percentage by mass of NaCl for the solution.         A) 14.22% B) 16.00 % C) 17.8% D) 19.05% E) 21.02% Part C) What is the concentration of NaCl in units of ppm?        A) 16,000 ppm B) 17,800 ppm C) 19,050 ppm D) 160,000 ppm E)        190,500 ppm Part D) What is its concentration in units of mole percent NaCl?        A) 3.75% B) 5.55% C) 5.87% D) 6.10% E) 16.0%

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13. Determine the molality of a 3.050 M solution of NaCl at 25o C, given that the density of the solution is 1.11401 g/mL at this temperature.

        A) 3.259 m B) 3.050 m C) 2.934 m D) 2.738 m E) 0.1600 m

Part B) What is the percentage by mass of NaCl for the solution.

        A) 14.22% B) 16.00 % C) 17.8% D) 19.05% E) 21.02%

Part C) What is the concentration of NaCl in units of ppm?

       A) 16,000 ppm B) 17,800 ppm C) 19,050 ppm D) 160,000 ppm E)        190,500 ppm

Part D) What is its concentration in units of mole percent NaCl?

       A) 3.75% B) 5.55% C) 5.87% D) 6.10% E) 16.0%

Expert Solution
Step 1

Given,

molarity of solution = 3.050 M

density = 1.11491 g/mL

Formula weight of NaCl = 58.5 g/mol

 

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