13. containing the points (1,0) and (-5, 6)

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Write an equation for the lines described below in all 3 forms (point - slope, slope intercept, and standard form)
### Problem 13

**Objective:**

Find the equation of the line containing the points (1, 0) and (-5, 6).

To find the equation of a line given two points, we need to use the standard form of a linear equation, which is given by:

\[ y = mx + c \]

where:
- \(m\) is the slope of the line,
- \(c\) is the y-intercept of the line.

Steps to determine the equation:

1. **Calculate the slope (m):**
   
   The slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by:

   \[ m = \frac{y_2 - y_1}{x_2 - x_1} \]

   Substituting the given points \((1, 0)\) and \((-5, 6)\):

   \[ m = \frac{6 - 0}{-5 - 1} = \frac{6}{-6} = -1 \]

2. **Calculate the y-intercept (c):**

   We use one of the points to find the y-intercept. Using point (1, 0) in the equation \( y = mx + c \):

   \[ 0 = (-1)(1) + c \]
   \[ 0 = -1 + c \]
   \[ c = 1 \]

3. **Form the equation of the line:**

   Substitute the values of \(m\) and \(c\) into the equation \( y = mx + c \):

   \[ y = -1x + 1 \]
   \[ \boxed{y = -x + 1} \]

**Explanation of the Graph:**

If you graph this line, it will pass through the points (1, 0) and (-5, 6). The slope of -1 indicates that for every unit increase in \(x\), the value of \(y\) decreases by 1 unit. The y-intercept at \(y = 1\) means the line crosses the y-axis at the point (0, 1).
Transcribed Image Text:### Problem 13 **Objective:** Find the equation of the line containing the points (1, 0) and (-5, 6). To find the equation of a line given two points, we need to use the standard form of a linear equation, which is given by: \[ y = mx + c \] where: - \(m\) is the slope of the line, - \(c\) is the y-intercept of the line. Steps to determine the equation: 1. **Calculate the slope (m):** The slope \(m\) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Substituting the given points \((1, 0)\) and \((-5, 6)\): \[ m = \frac{6 - 0}{-5 - 1} = \frac{6}{-6} = -1 \] 2. **Calculate the y-intercept (c):** We use one of the points to find the y-intercept. Using point (1, 0) in the equation \( y = mx + c \): \[ 0 = (-1)(1) + c \] \[ 0 = -1 + c \] \[ c = 1 \] 3. **Form the equation of the line:** Substitute the values of \(m\) and \(c\) into the equation \( y = mx + c \): \[ y = -1x + 1 \] \[ \boxed{y = -x + 1} \] **Explanation of the Graph:** If you graph this line, it will pass through the points (1, 0) and (-5, 6). The slope of -1 indicates that for every unit increase in \(x\), the value of \(y\) decreases by 1 unit. The y-intercept at \(y = 1\) means the line crosses the y-axis at the point (0, 1).
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