13. (b) Find the higest energy of the photon emitted by a downward electron transition in the Balmer series?
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A: The wavelength is given by: 1λ= R01n12-1n22 where R0 is the Rydberg constant
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A: Given Wavelength λ = 379.1 nm
Q: wavelength of 69.058 µm is observed in a hydrogen spectrum for a transition that ends in the nf = 11…
A: Wavelength (λ) = 69.058 µm nf = 11 ni = ?
Q: 13. (c) Find the higest energy of the photon emitted by a downward electron transition in the Layman…
A: Photons can be considered as packets of energy. Each packet will have an energy given by, E=hcλ…
Q: 12. (c) Find the shortest vacuum-wavelength photon emitted by a downward electron transition in the…
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A: Given that, n2= 1 n1 = 7 Rydberg constant R= 2.18×10-18 J
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A: We know, hcλ=V......................................(1) ANS:D 9.93*10^-16
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A: The wavelength is, E=hcλ⇒λ=hcE
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Q: (absorption) Brackett series Paschen series Lyman series (emission) Balmer series Paschen series…
A: Given:
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A: The electron on gaining energy jumps from lower orbit to higher orbit. It is just that correct…
Q: The electron of a hydrogen atom requires 1.633*10-18 J to be excited from n = 1 Bohr energy level to…
A: Energy of the photon, E = 1.633 x 10-18 J
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