13. A thin rod of length 2L carries a uniform linear charge density + lies along the x-axis with its midpoint centered atthe origin as shown. The electric potential V at point (A) a distance (L) from its right end, can be found by solvingone of the following integrals:3La) V = k-L2Lb) V = k0+Lc) V = √k--L3Ld) V=k-ܝλdx(x + L)L3L λdxe) V=SkLAdxa) 300b) True2.dx(2L-x)Adx(x+L)²Xb) 4802L-14. A point charge Q = +4 µC is fixed a distance x = 0.1 m from point A as shown in the figure. A charged particle ofq = 64 nC and mass m = 2 × 10-7 kg is released from rest at point A and moves along x-axis to infinity. What isthe ultimate speed (in m/s) of the particle at infinity?Oc) 540dqd) 600·L-e) 660x=0.1 m A----X15. All points on the perpendicular (AB) bisector of the line joining two equal but opposite charges have a potential ofzero and Electric field of zero.Aa) FalseB-XPage 4/4

A thin rod of length= 2L uniform linear charge density=+λ midpoint of rod centered at the origin.

13. A thin rod of length 2L carries a uniform linear charge density + lies along the x-axis with its midpoint centered at the origin as shown. The electric potential V at point (A) a distance (L) from its right end, can be found by solving one of the following integrals: 3L =Sk- L a) V= 2L b) V = [k Adx (x + L) Adx +L c) V = [k -L 3L Adx (x+L)² Adx (2L-x) d) V = fk- L 3L Adx e) V = fk² L X 2L- dq --X ----X

13. A thin rod of length 2L carries a uniform linear charge density + lies along the x-axis with its midpoint centered at the origin as shown. The electric potential V at point (A) a distance (L) from its right end, can be found by solving one of the following integrals: 3L =Sk- L a) V= 2L b) V = [k Adx (x + L) Adx +L c) V = [k -L 3L Adx (x+L)² Adx (2L-x) d) V = fk- L 3L Adx e) V = fk² L X 2L- dq --X ----X

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

13. A thin rod of length 2L carries a uniform linear charge density + lies along the x-axis with its midpoint centered at
the origin as shown. The electric potential V at point (A) a distance (L) from its right end, can be found by solving
one of the following integrals:
3L
a) V = k-
L
2L
b) V = k
0
+L
c) V = √k-
-L
3L
d) V=k-
ܝ
λdx
(x + L)
L
3L λdx
e) V=Sk
L
Adx
a) 300
b) True
2.dx
(2L-x)
Adx
(x+L)²
X
b) 480
2L-
14. A point charge Q = +4 µC is fixed a distance x = 0.1 m from point A as shown in the figure. A charged particle of
q = 64 nC and mass m = 2 × 10-7 kg is released from rest at point A and moves along x-axis to infinity. What is
the ultimate speed (in m/s) of the particle at infinity?
O
c) 540
dq
d) 600
·L-
e) 660
x=0.1 m A
----X
15. All points on the perpendicular (AB) bisector of the line joining two equal but opposite charges have a potential of
zero and Electric field of zero.
A
a) False
B
-X
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