13. A grindstone in the shape of a solid disk with diameter 0.520 m and a mass of 50.0 kg is rotating at 850 rev/min. You press against the rim with a normal force of 160 N (Fig. 10.44), and the grindstone comes to a rest in 7.50 s. Find the coefficient of friction between the axe and the grindstone. You can ignore friction in the bearings. (Dynamics method) LOON 850 vev/mn F160 N m= 50.0 kg Suks 520m' I ΣF=ma 2X= Ia [2=3m ²xx t=79 850ul-7 rad

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13 13 13 Please draw all free body diagrams, label all equations used and if there is an inertia equation, please solve for it, thanks!
13. A grindstone in the shape of a solid disk with diameter 0.520 m and a mass of 50.0 kg is rotating at
850 rev/min. You press against the rim with a normal force of 160 N (Fig. 10.44), and the grindstone comes to
a rest in 7.50 s. Find the coefficient of friction between the axe and the grindstone. You can ignore friction in
the bearings. (Dynamics method)
F160 N
m= 50.0 kg
LOON,
Suks
520m F
F=ma
2X= Ia
22= {/m²*
850 vev/mn
I=²
t=78
850ul-7 red
Transcribed Image Text:13. A grindstone in the shape of a solid disk with diameter 0.520 m and a mass of 50.0 kg is rotating at 850 rev/min. You press against the rim with a normal force of 160 N (Fig. 10.44), and the grindstone comes to a rest in 7.50 s. Find the coefficient of friction between the axe and the grindstone. You can ignore friction in the bearings. (Dynamics method) F160 N m= 50.0 kg LOON, Suks 520m F F=ma 2X= Ia 22= {/m²* 850 vev/mn I=² t=78 850ul-7 red
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