13. (a) Find g(1) so that fg() dt =4- +2-sin". (b) Evaluate g(t) dt using the Evaluation Theorem. (c) Evaluate g(t) dt by the area interpretation of the integral. Compare your answer with part (b) above. (d) Evaluate g(t) dt.

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I need help with 13

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---

### Integral Calculus Problems

**13.** 

(a) Find \( g(t) \) so that 

\[
\int g(t) \, dt = \frac{t}{2} \sqrt{4 - t^2} + 2 \cdot \sin^{-1} \frac{t}{2}
\]

(b) Evaluate 

\[
\int_{0}^{2} g(t) \, dt
\]

using the Evaluation Theorem.

(c) Evaluate 

\[
\int_{0}^{2} g(t) \, dt 
\]

by the area interpretation of the integral. Compare your answer with part (b) above.

(d) Evaluate 

\[
\int_{0}^{\sqrt{3}} g(t) \, dt
\]

**14.** 

\( v(t) \) is the velocity of a moving object measured in feet per minute.

---

This section focuses on practicing the evaluation of definite integrals and understanding their geometric interpretations.
Transcribed Image Text:Here is the transcribed text from the image, suitable for an educational website: --- ### Integral Calculus Problems **13.** (a) Find \( g(t) \) so that \[ \int g(t) \, dt = \frac{t}{2} \sqrt{4 - t^2} + 2 \cdot \sin^{-1} \frac{t}{2} \] (b) Evaluate \[ \int_{0}^{2} g(t) \, dt \] using the Evaluation Theorem. (c) Evaluate \[ \int_{0}^{2} g(t) \, dt \] by the area interpretation of the integral. Compare your answer with part (b) above. (d) Evaluate \[ \int_{0}^{\sqrt{3}} g(t) \, dt \] **14.** \( v(t) \) is the velocity of a moving object measured in feet per minute. --- This section focuses on practicing the evaluation of definite integrals and understanding their geometric interpretations.
Expert Solution
Step 1

a) To find g(t) so that g(t)dt=t24-t2+2sin-1t2

Using the fundamental theorem of calculus,

g(t)=ddtt24-t2+2sin-1t2

Solving this step by step,

Using (f+g)'=f'+g'

g(t)=ddtt24-t2+ddt2sin-1t2................................(1)

 

 

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