College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
![### Physics Problem: Calculating the Speed of a Car
#### Problem Statement
**Question 18:** What is the speed of an 800-kg car whose kinetic energy (KE) is 250 kJ?
#### Detailed Explanation
To solve this problem, we need to use the formula for kinetic energy:
\[ KE = \frac{1}{2}mv^2 \]
Where:
- \( KE \) is the kinetic energy
- \( m \) is the mass of the object
- \( v \) is the velocity (or speed) of the object
Given:
- \( KE = 250 \text{kJ} = 250,000 \text{J} \)
- \( m = 800 \text{kg} \)
We need to find the speed \( v \).
#### Step-by-Step Solution
1. **Start with the kinetic energy formula:**
\[ KE = \frac{1}{2}mv^2 \]
2. **Rearrange the formula to solve for \( v \):**
\[ v^2 = \frac{2 \cdot KE}{m} \]
\[ v = \sqrt{\frac{2 \cdot KE}{m}} \]
3. **Substitute the given values into the formula:**
\[ v = \sqrt{\frac{2 \cdot 250,000}{800}} \]
4. **Calculate the values step-by-step:**
\[ v = \sqrt{\frac{500,000}{800}} \]
\[ v = \sqrt{625} \]
\[ v = 25 \text{ m/s} \]
#### Final Answer
The speed of the 800-kg car with a kinetic energy of 250 kJ is **25 meters per second (m/s)**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1f3a9dd4-0825-4975-b3b1-0ebe0225a05a%2F628659bc-c128-4871-8cc7-db2ff978eedf%2Fawui7r6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Physics Problem: Calculating the Speed of a Car
#### Problem Statement
**Question 18:** What is the speed of an 800-kg car whose kinetic energy (KE) is 250 kJ?
#### Detailed Explanation
To solve this problem, we need to use the formula for kinetic energy:
\[ KE = \frac{1}{2}mv^2 \]
Where:
- \( KE \) is the kinetic energy
- \( m \) is the mass of the object
- \( v \) is the velocity (or speed) of the object
Given:
- \( KE = 250 \text{kJ} = 250,000 \text{J} \)
- \( m = 800 \text{kg} \)
We need to find the speed \( v \).
#### Step-by-Step Solution
1. **Start with the kinetic energy formula:**
\[ KE = \frac{1}{2}mv^2 \]
2. **Rearrange the formula to solve for \( v \):**
\[ v^2 = \frac{2 \cdot KE}{m} \]
\[ v = \sqrt{\frac{2 \cdot KE}{m}} \]
3. **Substitute the given values into the formula:**
\[ v = \sqrt{\frac{2 \cdot 250,000}{800}} \]
4. **Calculate the values step-by-step:**
\[ v = \sqrt{\frac{500,000}{800}} \]
\[ v = \sqrt{625} \]
\[ v = 25 \text{ m/s} \]
#### Final Answer
The speed of the 800-kg car with a kinetic energy of 250 kJ is **25 meters per second (m/s)**.
![**Problem 13**
**Question:**
A 700-kg horse, whose power output is 1.0 hp, is pulling a sled over the snow at 3.5 m/s. Find the force the horse exerts on the sled.
---
**Explanation:**
This problem involves calculating the force exerted by a horse while pulling a sled, given the horse's power output and the sled’s velocity. The relevant concepts include the relationship between power, force, and velocity.
---
**Solution:**
1. **Given Data:**
- Mass of the horse (\( m \)) = 700 kg
- Power output (\( P \)) = 1.0 hp (horsepower)
- Speed of the sled (\( v \)) = 3.5 m/s
2. **Conversion of Units:**
- 1 horsepower (hp) is equivalent to 745.7 watts (W).
Thus, power in watts:
\[ P = 1.0 \, \text{hp} \times 745.7 \, \frac{\text{W}}{\text{hp}} = 745.7 \, \text{W} \]
3. **Power Equation:**
The formula to relate power, force, and velocity is given by:
\[ P = F \times v \]
Where:
- \( P \) is the power,
- \( F \) is the force,
- \( v \) is the velocity.
4. **Calculate Force:**
Rearrange the equation to solve for force (\( F \)):
\[ F = \frac{P}{v} \]
Plug in the given values:
\[ F = \frac{745.7 \, \text{W}}{3.5 \, \text{m/s}} \approx 213 \, \text{N} \]
**Answer:**
The force the horse exerts on the sled is approximately 213 Newtons (N).
---
This solution incorporates the necessary steps to convert units, use the appropriate formula, and calculate the required force, making it suitable for educational purposes.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1f3a9dd4-0825-4975-b3b1-0ebe0225a05a%2F628659bc-c128-4871-8cc7-db2ff978eedf%2Ft7mpik_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 13**
**Question:**
A 700-kg horse, whose power output is 1.0 hp, is pulling a sled over the snow at 3.5 m/s. Find the force the horse exerts on the sled.
---
**Explanation:**
This problem involves calculating the force exerted by a horse while pulling a sled, given the horse's power output and the sled’s velocity. The relevant concepts include the relationship between power, force, and velocity.
---
**Solution:**
1. **Given Data:**
- Mass of the horse (\( m \)) = 700 kg
- Power output (\( P \)) = 1.0 hp (horsepower)
- Speed of the sled (\( v \)) = 3.5 m/s
2. **Conversion of Units:**
- 1 horsepower (hp) is equivalent to 745.7 watts (W).
Thus, power in watts:
\[ P = 1.0 \, \text{hp} \times 745.7 \, \frac{\text{W}}{\text{hp}} = 745.7 \, \text{W} \]
3. **Power Equation:**
The formula to relate power, force, and velocity is given by:
\[ P = F \times v \]
Where:
- \( P \) is the power,
- \( F \) is the force,
- \( v \) is the velocity.
4. **Calculate Force:**
Rearrange the equation to solve for force (\( F \)):
\[ F = \frac{P}{v} \]
Plug in the given values:
\[ F = \frac{745.7 \, \text{W}}{3.5 \, \text{m/s}} \approx 213 \, \text{N} \]
**Answer:**
The force the horse exerts on the sled is approximately 213 Newtons (N).
---
This solution incorporates the necessary steps to convert units, use the appropriate formula, and calculate the required force, making it suitable for educational purposes.
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