Homework Help is Here – Start Your Trial Now!
Math
Geometry
目 #13 i Prove or disprove that the point (√51,7) lies on the circle centered at the origin and containing the point (6, 8). SOLUTION The circle centered at the origin and containing the point (6,8) has the following radius. r =√(x-h)² + (y-k)² where x = h= ₁y = and k= So, r = and a point lies on the circle if and only if the distance from that point to the origin is The distance from (√51, 7) to the origin is d = √(x −h)² + (y-k)² where x, h=₁₂y=, and k = So, d = So, the point (√51,7) lies on the circle centered at the origin and containing the point (6,8). Previous Next

目 #13 i Prove or disprove that the point (√51,7) lies on the circle centered at the origin and containing the point (6, 8). SOLUTION The circle centered at the origin and containing the point (6,8) has the following radius. r =√(x-h)² + (y-k)² where x = h= ₁y = and k= So, r = and a point lies on the circle if and only if the distance from that point to the origin is The distance from (√51, 7) to the origin is d = √(x −h)² + (y-k)² where x, h=₁₂y=, and k = So, d = So, the point (√51,7) lies on the circle centered at the origin and containing the point (6,8). Previous Next

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
See similar textbooks
icon
Related questions
Question
BIG IDEAS MATH C #13 i Prove or disprove that the point (√51,7) lies on the circle centered at the origin and containing the point (6,8). SOLUTION The circle centered at the origin and containing the point (6,8) has the following radius. r=√(x −h)² + (y-k)² where x = ₁ h = ₂y= and k = So, r = and a point lies on the circle if and only if the distance from that point to the origin is The distance from (√51, 7) to the origin is W d = √(x −h)² + (y-k)² where x = ₁ h = ₂ y= and k = So, d = So, the point (√51, 7) lies on the circle centered at the origin and containing the point (6,8). Previous Next
Transcribed Image Text:BIG IDEAS MATH C #13 i Prove or disprove that the point (√51,7) lies on the circle centered at the origin and containing the point (6,8). SOLUTION The circle centered at the origin and containing the point (6,8) has the following radius. r=√(x −h)² + (y-k)² where x = ₁ h = ₂y= and k = So, r = and a point lies on the circle if and only if the distance from that point to the origin is The distance from (√51, 7) to the origin is W d = √(x −h)² + (y-k)² where x = ₁ h = ₂ y= and k = So, d = So, the point (√51, 7) lies on the circle centered at the origin and containing the point (6,8). Previous Next
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
Elementary Geometry for College Students
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS