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= 13, an = {3an-1 A. D A aj = 3, ap = 133 . a3 = 3,3,3 = ਤਿਤਿਓ D B. 1 = 3. a2 = 33 . a3 = 93, a = 27 (3 D C, aı = 3, a2 = 3, a3 = 313, a4 = 9 . .= 3,3,33 3 aa ਮਿਲੀਆਂ D D a = 3, a = 3. a = ਮਿਲਿਓ . ਫ਼ = D. 13 {3

= 13, an = {3an-1 A. D A aj = 3, ap = 133 . a3 = 3,3,3 = ਤਿਤਿਓ D B. 1 = 3. a2 = 33 . a3 = 93, a = 27 (3 D C, aı = 3, a2 = 3, a3 = 313, a4 = 9 . .= 3,3,33 3 aa ਮਿਲੀਆਂ D D a = 3, a = 3. a = ਮਿਲਿਓ . ਫ਼ = D. 13 {3

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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↑ The sequence is defined recursively. Write the first four terms. a₁ = √√3; a = √√3an - 1 A. a₁ = √3, a2 = √3√3 a3 = √3√3√3,24 = √3/3√3√3 OB. a₁ =√√3, a2=3√3, a3 = 9√√3, a4=27√/3 Oc. a1 = √3, a₂ = 3, a3 = 3√3, a4 = 9 OD. a₁ = √3, a2 = √√3, 23= √√√√3. = √√√√√√³ a4 =
Transcribed Image Text:↑ The sequence is defined recursively. Write the first four terms. a₁ = √√3; a = √√3an - 1 A. a₁ = √3, a2 = √3√3 a3 = √3√3√3,24 = √3/3√3√3 OB. a₁ =√√3, a2=3√3, a3 = 9√√3, a4=27√/3 Oc. a1 = √3, a₂ = 3, a3 = 3√3, a4 = 9 OD. a₁ = √3, a2 = √√3, 23= √√√√3. = √√√√√√³ a4 =
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