13 ABCD is a trapecium with ABDC. A line parallel to AC intersects AB at X at Y Prove that ar (ADX)=ar (ACY) Hi: Join CX)

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
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REDMI NOTE 5 PRO
MI DUAL CAMERA
of the village dvided to take over some portion of his ploi lil dle tr ie Come
construct a Health Contre, Iwaari agrees to the above proposal with the co
hat he shoukt e given equal amount of land in lieu of his land adjoining his a
as to form a triangular plot. Explain how this proposal will be implemented.
13 ABCD is a trapecium with ABIDC. A line parallel to AC intersects AB at X
at Y Prove that ar (ADX)= ar (ACY)
(o:Join CX)
and
14 In Fig 9.28, AP IBQ CR Prove that
ar (AQC)=ar (PRR)
15. Diagonals AC and BD of a quadrilateral
ABCD interseet at O in such a way that
ar (AOD)= ar (BOC) Prove that ABCD is a
Fig. 9.28
rapeziam
16 In Fig 9.29, ar (DRC) = ar (DPC) and
ar (BDP) = ar (ARC) Show that both the
quadrilaterals ABCD and DCPR are
trapeziums
B.
D.
R.
Fig. 9.29
EXERCISE 9.4 (Optional)*
1. Parallelogram ABCD and rectangle ABEF are on the same base AB and have ec
areas. Show that the perimeter of the parallelogram is greater than that of the rectan.
2 In Fig. 930, D and E are two points on BC
such that BD = DE = EC. Show that
ar (ABD)= ar (ADE)=ar (AEC).
Can you now answer the question that you have
left in the "Introduction' of this chapter, whether
the field of Budhia has been actually divided
into three parts of equal area?
B.
D.
Fig. 9,30
"These exercises are not from examination point of view,
Transcribed Image Text:REDMI NOTE 5 PRO MI DUAL CAMERA of the village dvided to take over some portion of his ploi lil dle tr ie Come construct a Health Contre, Iwaari agrees to the above proposal with the co hat he shoukt e given equal amount of land in lieu of his land adjoining his a as to form a triangular plot. Explain how this proposal will be implemented. 13 ABCD is a trapecium with ABIDC. A line parallel to AC intersects AB at X at Y Prove that ar (ADX)= ar (ACY) (o:Join CX) and 14 In Fig 9.28, AP IBQ CR Prove that ar (AQC)=ar (PRR) 15. Diagonals AC and BD of a quadrilateral ABCD interseet at O in such a way that ar (AOD)= ar (BOC) Prove that ABCD is a Fig. 9.28 rapeziam 16 In Fig 9.29, ar (DRC) = ar (DPC) and ar (BDP) = ar (ARC) Show that both the quadrilaterals ABCD and DCPR are trapeziums B. D. R. Fig. 9.29 EXERCISE 9.4 (Optional)* 1. Parallelogram ABCD and rectangle ABEF are on the same base AB and have ec areas. Show that the perimeter of the parallelogram is greater than that of the rectan. 2 In Fig. 930, D and E are two points on BC such that BD = DE = EC. Show that ar (ABD)= ar (ADE)=ar (AEC). Can you now answer the question that you have left in the "Introduction' of this chapter, whether the field of Budhia has been actually divided into three parts of equal area? B. D. Fig. 9,30 "These exercises are not from examination point of view,
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