13 1 point Find the midpoint of the line segment. If needed, round to the nearest tenth. you must upload a photo of your work for this problem at the end of the quiz to receive credit M= type your answer. -4 -2 2 41 u must uplod a photo of youcwork for this problem at the end of the quir to

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Graph Interpretation and Midpoint Calculation

**Problem Statement:**

Find the **midpoint** of the line segment. If needed, round to the nearest **tenth**.

**Instructions:**
- You must upload a **photo of your work** for this problem at the end of the quiz to receive credit.

**Answer Format:**

\[ M = \text{{type your answer here}} \]

---

### Detailed Diagram Description:

The image displays a Cartesian plane (coordinate grid) with:
- Horizontal axis labeled \( x \) ranging from -4 to 4.
- Vertical axis labeled \( y \) ranging from -4 to 4.
- A line segment with endpoints clearly marked.

**Specific Points:**
- The line segment starts at point \((-3, 3)\).
- The line segment ends at point \((3, -1)\).

### Graph Explanation:

- The \( x \)-axis intersects at (0,0) and extends both positively and negatively up to 4 units.
- The \( y \)-axis also intersects at (0,0) and extends similarly to 4 units in both directions.
- Each grid square represents one unit length.

---

### Additional Notes:

- Calculating the midpoint involves averaging the \( x \) and \( y \) coordinates of the endpoints.
- **Formula for Midpoint \( M \)** of a line segment with endpoints \((x_1, y_1)\) and \((x_2, y_2)\):

\[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \]

Applying the given endpoints:
\[ M = \left( \frac{-3 + 3}{2}, \frac{3 + (-1)}{2} \right) \]

\[ M = \left( \frac{0}{2}, \frac{2}{2} \right) \]

\[ M = \left( 0, 1 \right) \]

Thus, the midpoint \( M \) is \( (0, 1) \).

Ensure to upload the detailed calculation for verification and credit.

---

### Submission:

- Ensure to review your calculation.
- Upload the photo as required for credit recognition.

For further questions or clarifications, refer to your course instructor or the help section.
Transcribed Image Text:--- ### Graph Interpretation and Midpoint Calculation **Problem Statement:** Find the **midpoint** of the line segment. If needed, round to the nearest **tenth**. **Instructions:** - You must upload a **photo of your work** for this problem at the end of the quiz to receive credit. **Answer Format:** \[ M = \text{{type your answer here}} \] --- ### Detailed Diagram Description: The image displays a Cartesian plane (coordinate grid) with: - Horizontal axis labeled \( x \) ranging from -4 to 4. - Vertical axis labeled \( y \) ranging from -4 to 4. - A line segment with endpoints clearly marked. **Specific Points:** - The line segment starts at point \((-3, 3)\). - The line segment ends at point \((3, -1)\). ### Graph Explanation: - The \( x \)-axis intersects at (0,0) and extends both positively and negatively up to 4 units. - The \( y \)-axis also intersects at (0,0) and extends similarly to 4 units in both directions. - Each grid square represents one unit length. --- ### Additional Notes: - Calculating the midpoint involves averaging the \( x \) and \( y \) coordinates of the endpoints. - **Formula for Midpoint \( M \)** of a line segment with endpoints \((x_1, y_1)\) and \((x_2, y_2)\): \[ M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) \] Applying the given endpoints: \[ M = \left( \frac{-3 + 3}{2}, \frac{3 + (-1)}{2} \right) \] \[ M = \left( \frac{0}{2}, \frac{2}{2} \right) \] \[ M = \left( 0, 1 \right) \] Thus, the midpoint \( M \) is \( (0, 1) \). Ensure to upload the detailed calculation for verification and credit. --- ### Submission: - Ensure to review your calculation. - Upload the photo as required for credit recognition. For further questions or clarifications, refer to your course instructor or the help section.
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