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Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Determine the total resistance (RAB) and the current I . Can we also determine branch
currents ? How? (All resistors are Ohm)

### Series-Parallel Circuit Analysis In this diagram, we present a series-parallel circuit which includes resistors, a voltage source, and labeled nodes. The key elements of this circuit are as follows: 1. **Voltage Source (12V)**: The circuit is powered by a 12V DC power supply, represented by a circle with a plus and minus sign, positioned on the left side. It delivers electrical energy to the circuit. 2. **Current Direction (I)**: The current direction is denoted by a red arrow on node A, indicating the flow of electrons in the circuit. 3. **Resistors**: - **Series Resistors (3Ω each)**: There are two resistors, each with a resistance of 3 ohms, positioned immediately after nodes A and B. - **Parallel Resistive Network**: - One branch consists of a 2Ω resistor, another with a 6Ω resistor, and yet another branch with two 4Ω resistors in series. - **Combined Parallel Network**: These resistors form a combination of series and parallel networks, affecting the total resistance and current distribution. 4. **Nodes**: - **Node A**: Located at the junction of the 12V source and the first 3Ω resistor. - **Node B**: Positioned at the junction of the 3Ω resistor on the other side of the circuit. ### Detailed Description of the Circuit: - The circuit starts with the 12V source on the left and a current arrow indicating the current flow starting at node A. - After node A, the current flows through a 3Ω resistor. - Following this resistor, the circuit splits into three parallel branches: - The first branch contains a 2Ω resistor. - The second branch contains a 6Ω resistor. - The third branch contains two 4Ω resistors in series, adding up to 8Ω. - These branches then converge, connecting to another set of series resistors (2Ω and 3Ω) before reaching node B. - Both nodes A and B are highlighted with red dots for clarity. ### Analyzing the Circuit: To calculate the equivalent resistance of this series-parallel circuit, follow these steps: 1. **Identify Parallel Resistors**: - Combine the resistances in each branch using the parallel resistance formula. - Calculate the equivalent resistance of the combined branches. 2. **
Transcribed Image Text:### Series-Parallel Circuit Analysis In this diagram, we present a series-parallel circuit which includes resistors, a voltage source, and labeled nodes. The key elements of this circuit are as follows: 1. **Voltage Source (12V)**: The circuit is powered by a 12V DC power supply, represented by a circle with a plus and minus sign, positioned on the left side. It delivers electrical energy to the circuit. 2. **Current Direction (I)**: The current direction is denoted by a red arrow on node A, indicating the flow of electrons in the circuit. 3. **Resistors**: - **Series Resistors (3Ω each)**: There are two resistors, each with a resistance of 3 ohms, positioned immediately after nodes A and B. - **Parallel Resistive Network**: - One branch consists of a 2Ω resistor, another with a 6Ω resistor, and yet another branch with two 4Ω resistors in series. - **Combined Parallel Network**: These resistors form a combination of series and parallel networks, affecting the total resistance and current distribution. 4. **Nodes**: - **Node A**: Located at the junction of the 12V source and the first 3Ω resistor. - **Node B**: Positioned at the junction of the 3Ω resistor on the other side of the circuit. ### Detailed Description of the Circuit: - The circuit starts with the 12V source on the left and a current arrow indicating the current flow starting at node A. - After node A, the current flows through a 3Ω resistor. - Following this resistor, the circuit splits into three parallel branches: - The first branch contains a 2Ω resistor. - The second branch contains a 6Ω resistor. - The third branch contains two 4Ω resistors in series, adding up to 8Ω. - These branches then converge, connecting to another set of series resistors (2Ω and 3Ω) before reaching node B. - Both nodes A and B are highlighted with red dots for clarity. ### Analyzing the Circuit: To calculate the equivalent resistance of this series-parallel circuit, follow these steps: 1. **Identify Parallel Resistors**: - Combine the resistances in each branch using the parallel resistance formula. - Calculate the equivalent resistance of the combined branches. 2. **
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