Homework Help is Here – Start Your Trial Now!
Engineering
Electrical Engineering
12V +1 A 3 ww www B 3 ww 6 2 www www 2 ww 4 4

12V +1 A 3 ww www B 3 ww 6 2 www www 2 ww 4 4

Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter7: Parallel Circuits
Section: Chapter Questions
Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....
See similar textbooks
icon
Related questions
Question

Determine the total resistance (RAB) and the current I . Can we also determine branch
currents ? How? (All resistors are Ohm)

### Series-Parallel Circuit Analysis In this diagram, we present a series-parallel circuit which includes resistors, a voltage source, and labeled nodes. The key elements of this circuit are as follows: 1. **Voltage Source (12V)**: The circuit is powered by a 12V DC power supply, represented by a circle with a plus and minus sign, positioned on the left side. It delivers electrical energy to the circuit. 2. **Current Direction (I)**: The current direction is denoted by a red arrow on node A, indicating the flow of electrons in the circuit. 3. **Resistors**: - **Series Resistors (3Ω each)**: There are two resistors, each with a resistance of 3 ohms, positioned immediately after nodes A and B. - **Parallel Resistive Network**: - One branch consists of a 2Ω resistor, another with a 6Ω resistor, and yet another branch with two 4Ω resistors in series. - **Combined Parallel Network**: These resistors form a combination of series and parallel networks, affecting the total resistance and current distribution. 4. **Nodes**: - **Node A**: Located at the junction of the 12V source and the first 3Ω resistor. - **Node B**: Positioned at the junction of the 3Ω resistor on the other side of the circuit. ### Detailed Description of the Circuit: - The circuit starts with the 12V source on the left and a current arrow indicating the current flow starting at node A. - After node A, the current flows through a 3Ω resistor. - Following this resistor, the circuit splits into three parallel branches: - The first branch contains a 2Ω resistor. - The second branch contains a 6Ω resistor. - The third branch contains two 4Ω resistors in series, adding up to 8Ω. - These branches then converge, connecting to another set of series resistors (2Ω and 3Ω) before reaching node B. - Both nodes A and B are highlighted with red dots for clarity. ### Analyzing the Circuit: To calculate the equivalent resistance of this series-parallel circuit, follow these steps: 1. **Identify Parallel Resistors**: - Combine the resistances in each branch using the parallel resistance formula. - Calculate the equivalent resistance of the combined branches. 2. **
Transcribed Image Text:### Series-Parallel Circuit Analysis In this diagram, we present a series-parallel circuit which includes resistors, a voltage source, and labeled nodes. The key elements of this circuit are as follows: 1. **Voltage Source (12V)**: The circuit is powered by a 12V DC power supply, represented by a circle with a plus and minus sign, positioned on the left side. It delivers electrical energy to the circuit. 2. **Current Direction (I)**: The current direction is denoted by a red arrow on node A, indicating the flow of electrons in the circuit. 3. **Resistors**: - **Series Resistors (3Ω each)**: There are two resistors, each with a resistance of 3 ohms, positioned immediately after nodes A and B. - **Parallel Resistive Network**: - One branch consists of a 2Ω resistor, another with a 6Ω resistor, and yet another branch with two 4Ω resistors in series. - **Combined Parallel Network**: These resistors form a combination of series and parallel networks, affecting the total resistance and current distribution. 4. **Nodes**: - **Node A**: Located at the junction of the 12V source and the first 3Ω resistor. - **Node B**: Positioned at the junction of the 3Ω resistor on the other side of the circuit. ### Detailed Description of the Circuit: - The circuit starts with the 12V source on the left and a current arrow indicating the current flow starting at node A. - After node A, the current flows through a 3Ω resistor. - Following this resistor, the circuit splits into three parallel branches: - The first branch contains a 2Ω resistor. - The second branch contains a 6Ω resistor. - The third branch contains two 4Ω resistors in series, adding up to 8Ω. - These branches then converge, connecting to another set of series resistors (2Ω and 3Ω) before reaching node B. - Both nodes A and B are highlighted with red dots for clarity. ### Analyzing the Circuit: To calculate the equivalent resistance of this series-parallel circuit, follow these steps: 1. **Identify Parallel Resistors**: - Combine the resistances in each branch using the parallel resistance formula. - Calculate the equivalent resistance of the combined branches. 2. **
Expert Solution
steps

Step by step

Solved in 3 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Transfer Function of Ladder Circuit
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
SEE MORE TEXTBOOKS