Please let me know if I solved this question correctly, if not let me know where I went wrong Factor denominator :2x + x12x³6x² + 6x6x4+x²=So, B=-612x³6x²6x-bx² (x²+1)x² (x²+1)dx =:1Decomposition:Solve for constants: A x (x²+1) + B (x²+1) + ((x+b) x ²A BXx+CA = 6₁+2+(x+D(x²+1)= Ax³+Ax + Bx²+B+ (x³ +Dx²B+D=-6(-6)+1=-6D=0+A+ C = 12(6)+c=12c = 6Integrate S (A++ (x+5) dx = f(-42 + 6×20) dx = 6 lalyl + = + 3 \n (2²+1) +B:Cx+D6x1x1C

Answered: 12r³6x²+62-6 x4+x² dz= +C

Math

Calculus

12r³6x²+62-6 x4+x² dz= +C

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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