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12r³6x²+62-6 x4+x² dz= +C

12r³6x²+62-6 x4+x² dz= +C

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Factor denominator : 2 x + x 12x³6x² + 6x6 x4+x² = So, B=-6 12x³6x²6x-b x² (x²+1) x² (x²+1) dx = : 1 Decomposition: Solve for constants: A x (x²+1) + B (x²+1) + ((x+b) x ² A B Xx +C A = 6₁ + 2 + (x+D (x²+1) = Ax³+Ax + Bx²+B+ (x³ +Dx² B+D=-6 (-6)+1=-6 D=0 + A+ C = 12 (6)+c=12 c = 6 Integrate S (A++ (x+5) dx = f(-42 + 6×20) dx = 6 lalyl + = + 3 \n (2²+1) + B : Cx+D 6 x 1x1 C
Transcribed Image Text:Factor denominator : 2 x + x 12x³6x² + 6x6 x4+x² = So, B=-6 12x³6x²6x-b x² (x²+1) x² (x²+1) dx = : 1 Decomposition: Solve for constants: A x (x²+1) + B (x²+1) + ((x+b) x ² A B Xx +C A = 6₁ + 2 + (x+D (x²+1) = Ax³+Ax + Bx²+B+ (x³ +Dx² B+D=-6 (-6)+1=-6 D=0 + A+ C = 12 (6)+c=12 c = 6 Integrate S (A++ (x+5) dx = f(-42 + 6×20) dx = 6 lalyl + = + 3 \n (2²+1) + B : Cx+D 6 x 1x1 C
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