127.[HSC] (i) (ii) The complex numbers z = cos 0 + i sin 0 and w = cos α + isinα, -π<0≤π and -π<α ≤π, satisfy 1+z+w = 0. By considering the real and imaginary parts of 1+z+w, or otherwise, show that 1,z and w from the vertices of an equilateral triangle in the Argand diagram. Hence, or otherwise, show that if the three non-zero complex numbers 2i, Z₁ and Z₂ satisfy |2i| = |Z₁| = |Z₂ AND 2i+Z₁ + Z2₂ = 0 then they form the vertices of an equilateral triangle in the Argand diagram

Advanced Engineering Mathematics
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Chapter2: Second-order Linear Odes
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127.[HSC]
(i)
(ii)
The complex numbers z = cos 0 + i sin 0 and w = cos α + isinα, -π<0≤π and -π<α ≤π,
satisfy 1+z+w = 0. By considering the real and imaginary parts of 1+z+w, or otherwise, show that
1,z and w from the vertices of an equilateral triangle in the Argand diagram.
Hence, or otherwise, show that if the three non-zero complex numbers 2i, Z₁ and Z₂ satisfy
|2i| = |Z₁| = |Z₂ AND 2i+Z₁ + Z2₂ = 0
then they form the vertices of an equilateral triangle in the Argand diagram
Transcribed Image Text:127.[HSC] (i) (ii) The complex numbers z = cos 0 + i sin 0 and w = cos α + isinα, -π<0≤π and -π<α ≤π, satisfy 1+z+w = 0. By considering the real and imaginary parts of 1+z+w, or otherwise, show that 1,z and w from the vertices of an equilateral triangle in the Argand diagram. Hence, or otherwise, show that if the three non-zero complex numbers 2i, Z₁ and Z₂ satisfy |2i| = |Z₁| = |Z₂ AND 2i+Z₁ + Z2₂ = 0 then they form the vertices of an equilateral triangle in the Argand diagram
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