Answered: 1241 Energy vs wavelength relation is… | bartleby

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Energy vs wavelength relation is given by, E(eV) =-
1241
Energy of H-
2(nm)
atom in the ground state is -13.6 ev as from the relation
EeV) =-13.6 (eV). Find that in which transition of hydrogen atom is
the wavelength of 486.1 nm produced? To which series does it belong?

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