120 110 100 90 80 70 0.0 0.5 1.0 Sample -1.0 -2.0 O O 60 -1.5 O O Scatterplot for average O 80 -1.0 O 100 -0.5 Body Weight (kg) O Q-Q Plot O 120 0.0 0.5 Theoretical Quantiles O 1.0 T 140 1.5 O stdres 0.0 0.5 1.0 -1.0 -2.0 stdres 1.0 0.5 -0.5 0.0 -1.0 -2.0 -1.5 Std residuals versus explanatory variable O 60 O 80 O 80 O O 90 Body Weight (kg) Std residuals versus fits O 100 O T 100 fits O 120 110 120 140 O T 130

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30 of 68 ge 13. Your teacl 11. A consumers group recently tested 100compact fluorescent light bulbs and recorded their lifetimes. The shows the boys ages chart shows the results. 2 to 20 years: Boys Body mass index-for-age Lifetime (h) Frequency Date Age Weight Stat 5000-6000 7 6000-7000 12 7000-8000 34 8000-9000 27 9000-10 000 10 *To Calculate BMI: Weight (kg or Weight (Ib) - Sta BMI 10 000–11 000 27 11 000-12 000 26 25- a) Make a box and whisker plot of the 24 23 data. 22 b) Make a histogram of the data and mark the quartiles on it. 21 20 19 c) Describe the middle 50% of the data. 18 17 d) Identify any outliers. 16 15 12 Agencies trocl o 1:

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Refer to the table to the right summarizing measured amounts of serum cotinine (ng/mL) from a sample of smokers. When nicotine is absorbed by the body, cotinine is produced. How many subjects are included in the summary? Is it possible to identify the exact values of all of the original cotinine measurements? Cotinine (ng/mL) 0-99 100-199 200-299 300-399 400-499 How many subjects are included in the summary? (Type a whole number.) Is it possible to identify the exact values of all of the original cotinine measurements? Frequency 10 14 15 3 2 OA. Yes. The exact data values are equally spaced numbers between the limits of each class. The number of equally spaced numbers is determined by the frequency in each class. OB. No. A frequency table only shows percentages of the sample in each category. OC. No. A frequency table only shows frequencies of data values in each category. OD. Yes. The data values are the frequencies shown in the table.

(no subject) - noellekuX Downloads Answered: A biologist x /1049172/quizzes/3364780/take "octors as. E Prescription opioid... Overview of Mental... Netflix 2 E Doctor or Drug Dea... Question 5 1.5 A research student is working with a culture of bacteria that doubles in size every twenty minutes. The initial population count was 1350 bacteria. Rounding to five significant digits, write an equation representing this situation in the form: A (t) = Aoekt Ao = k = What is the population size after 3 hours (round to the nearest thousand)? thousand Question 6 1.5 pts A biologist recorded a count of 360 bacteria present in a culture after 5 minutes and 1000 bacteria present after 20 minutes. Write an exponential equation representing this situation in the form: A (t) = Aget 4. 360^E fround to tbe arest whole number

Prevalence of a disease in a certain population is 5.0 / 1000. If one million people live in that population, how many have the disease?

Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts​ (a) through​ (c) below.      ​Tinterval (13.046,22.15) x=17.598 Sx=16.01712719 n=50

With 12 degrees of freedom, the values of x/2 = x0.025 and x- a/2 = x0,975 can be found from a chi- square table. Area in Upper Tail Degrees of Freedom 0.995 0.99 0.975 0.95 0.90 0.10 0.05 0.025 0.01 0.05 12 3.074 3.571 4.404 5.226 6.304 18.549 21.026 23.337 26.217 28.300 ,2 = x0.025, move along the row for 12 degrees of freedom until reaching the column To find the value of xa/2 for an upper tail area of 0.025. Find x0.025, rounding the result to three decimal places. x0.025 Use this same process to find x0.975, rounding the result to three decimal places. x0.975 Submit Skip (you cannot come back)

A photoconductor film is manufactured at a nominal thickness of 25 mils. The product engineer wishes to increase the mean speed of the film, and believes that this can be achieved by reducing the thickness of the film to 20 mils. Eight samples of each film thickness are manufactured in a pilot production process, and the film speed (in microjoules per square inch) is measured. For the 25-mil film, the sample data result is = 1.15 and 81 = 0.11, while for the 20-mil film, the data yield 2 = 1.06 and 82 = 0.09. Note that an increase in film speed vould lower the value of the observation in microjoules per square inch. (a) Do the data support the claim that reducing the film thickness increases the mean speed of the film? Use a = 0.10 and assume that the two population variances are equal and the underlying population of film speed is normally distributed. What is the P-value for this test? Round your answer to three decimal places (e.g. 98.765). The data the claim that reducing the film…