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Given the figures, give the FBD (free-body diagram) for each box, A and B.
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- option ommand 15. Two boxes are plaçed on a horizontal frictionless surface, as shown above. Box A has a mass of 10 kg and box B has a mass of 16 kg. A force of 54 N is pushing box A. F A a) Draw a free-body diagram for each block showing all applied forces to scale. Next to each diagram show the direction of the acceleration of that object. b) Find the acceleration of the system of two boxes. c) Find the force of contact that each box exerts on its neighbor.Answer Questions 2,3, and 4 PleaseThe diagram at right shows a free-body diagram for an object that is moving to the right. Which arrow most closely approximates the direction of the particle's acceleration? А H В F. 2 C F 4 F. F D E O A O E O F
- How do I solve 1a, 1b, 1cA horizontal force, F1, and a force F2 acting at an angle of 0 to the horizontal, are applied to a block of mass m. The block is moving to the right at a constant velocity across a rough surface. y F, Use Fk to denote the force of kinetic friction. m Please use the interactive area below to draw the Free Body Diagram for the block. 1 Add Force S Reset All Fn v 90 vx Fg v 270 vx F1 v0 Fk v 180 vx Fn Fk F1 Fg Ftotal,x:0 Ftotal,y: 0 Submit I give up! Hint FeedbackA sports car with a mass of 1,385 kg is at rest on a flat, horizontal road. 5.4 s later, that car is moving forward at a speed of 90 mph. Calculate the acceleration of the car and the average net force acting on the car.For this problem: Draw a diagram of the motion Draw a free body diagram.Write your N2 Law equationList your kinematics variablesSolve the algebraic equation using variables.Plug in your information and solve.
- Block 1 (13 kg) is setting on the floor of an elevator. A rope pulls vertically up on block 1 with a tension of 5 N. The elevator is moving downward with a decreasing speed and the magnitude of the acceleration is 4 m/s². On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. NET force on Block 1 Fnet1 i + Submit Answer Tries 0/2 FORCES on BLOCK 1 Weight force on block 1 by Earth W1E = i + jN Submit Answer Tries 0/2 Tension Force on block 1 by Rope T1R = i + jN Submit Answer jN Tries 0/2 Submit Answer Normal force on block 1 by Surface N1S = i + jN Tries 0/2Draw a complete force diagram of the ball and label all forces. Find the magnitude of the acceleration of the railway car.An elevator shown below filled with passengers has a mass of 1450 kg. The elevator does motions (a) through (c) in succession. For each of the parts below draw a free body diagram of the elevator in your notebook for each of the parts (a) to (c). Draw the acceleration and velocity vectors in the boxes. For each part, are the vectors for tension in the string and weight of the elevator of equal lengths or unequal lengths. (a) The elevator accelerates upward from rest at a rate of 0.7 ms2 for 1.2 s. (i) Newton’s Second Law in the y-direction can be written as: Instruction: If a is the magnitude of the acceleration, pick "1" if the acceleration is upwards, pick "-1" if the acceleration is downwards, and pick "0" if there is no acceleration. ∑Fy=T−meg= ×mea (ii) Calculate the tension in the cable supporting the elevator. T= N (iii) How high has the elevator moved during this time? Δy= m (iv) Calculate the velocity of the…
- A 5.0-kg bag of potatoes sits on the bottom of a stationary shopping cart. (a) Sketch a free-body diagram for the bag of potatoes.(b) Now suppose the cart moves with a constant velocity. Howdoes this affect your free-body diagram? ExplainComplete solution with free body diagram. ThanksBlock 1 (2 kg) is setting on the floor of an elevator. A hand pushes vertically down on block 1 with a force of 26.0 N. The elevator is moving downward with an increasing speed and the magnitude of the acceleration is 7 m/s2.On a sheet of paper, draw the free body diagram for block 1 using the two-subscript notation from class. After completing the free body diagram, enter below each force and its x & y-components. Remember that the x-component is the "i" component and the y-component is the "j" component. NET force on Block 1Fnet1 = i + j N FORCES on BLOCK 1Weight force on block 1 by EarthW1E = i + j N Normal force on block 1 by HandN1H = i + j N Normal force on block 1 by SurfaceN1S = i + j N