**Question:**12.4 mL of a urine sample has a mass of 0.13 g. What is the specific gravity of the sample? Report correct units (if any).**Answer choices:**- ○ 0.010- ○ 95 g/mL- ○ 0.010 g/mL- ○ 95**Explanation:**Specific gravity is a dimensionless quantity that compares the density of a substance to the density of water. The formula to calculate specific gravity (SG) is:\[ \text{SG} = \frac{\text{Density of the substance}}{\text{Density of water}} \]Where:- The density of the substance (urine in this case) = $\frac{\text{Mass}}{\text{Volume}}$- The density of water is typically $1 \, \text{g/mL}$ at 4°C.Given data:- Volume of the urine sample (V) = 12.4 mL- Mass of the urine sample (m) = 0.13 gFirst, calculate the density of the urine sample:\[ \text{Density of urine sample} = \frac{0.13 \, \text{g}}{12.4 \, \text{mL}} \approx 0.0105 \, \text{g/mL} \]Next, calculate the specific gravity of the urine sample:\[ \text{SG} = \frac{0.0105 \, \text{g/mL}}{1 \, \text{g/mL}} \approx 0.0105 \]Since none of the answer choices match the exact calculated value, the closest correct option that represents the specific gravity is:- ○ 0.010

we have to calculate the specific gravity of urine sample

Answered: 12.4 mL of a urine sample has a mass of…

12.4 mL of a urine sample has a mass of 0.13 g. What is the specific gravity of the sample. Report correct units (if any). 0.010 95 g/mL 0.010 g/mL 95

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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