12.3 Draw an expression tree for each of the following expressions. a. 1 b. 1+5*3-4/2 c. 1+5* (3-4)/2 d. (1+5)*(3-4/2) e. (1 + (5 * (3 − (4/2))))

12.3 Draw an expression tree for each of the following expressions. a. 1 b. 1+53-4/2 c. 1+5 (3-4)/2 d. (1+5)(3-4/2) e. (1 + (5 (3 − (4/2))))

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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GRADED ACTIVITY #6 (M8.1): REPETITION CONTROL STRUCTURE (WHILE, DO-WHILE) Instruction: A mathematician named Ulam proposed generating a sequence of numbers from any positive integer N greater than 1 using the following procedure: If N is 1, stop. If N is even, replace it with N/2. If N is odd, replace it with 3 * N + 1. Continue with this process until N reaches 1. Here are some examples of the Ulam sequence for the first few integers. 2, 1 3, 10, 5, 16, 8, 4, 2, 1 4, 2, 1 5, 16, 8, 4, 2, 1 6, 3, 10, 5, 16, 8, 4, 2, 1 Write a Java program using while/do-while that accepts as input an integer value N (assume N> 1) and prints out the Ulam sequence that begins with the input value N. Sample Input/Output: Depicted below are sample outputs when the program is executed (the items in bold characters are input from the user, while the items in bold italic are calculated and printed by the program): Input N: 14 Ulam Sequence: Input N: 5 Ulam Sequence: 5, 16, 8, 4, 2, 1 14, 7, 22, 11, 34, 17,…
1. Build PDA to generate all strings of the form 0n12n+3 where n>=0 2. Build CFG to generate all strings of the form 0n12n+3 where n>=0 3. Build PDA to generate all strings of the form 0n1 n where n is even 4. Build CFG to generate all strings of the form 0n1 n where n is even 5. Build PDA to generate all strings of the form 1 n 0 m, where m and n are even, and m>n 6. Build CFG to generate all strings of the form 1 n 0 m 1 n, where m and n are greater or equal to 0. 7. Build PDA to generate all strings of the form w11, where w is a palindrome containing 1's and 0's. For example, the following strings should be generated: • 01011 (010 is a palindrome, and 11 is the ending) • 1101111 (11011 is a palindrome, and 11 is the ending) • 01011 (010 is a palindrome, and 11 is the ending) 8. Build CFG to generate all strings of the form w11, where w is a palindrome containing 1's and 0's. 9. Build PDA which generates all non-empty strings with equal number of 1’s and 0’s \ 10. Please…
14.3: List all elements of given set expression. Jump to level 1 A = {x e Z: x is odd } B = {2, 5, 9 } C = {1, 5, 7 } (CNB)-A= {Ex: 3, 6 } 3 7. Check Next et subtraction is not associative. showing that subtraction is not associative: A- (B-C) # (A- B)- C.
a 92 93 a 91 a, b FIGURE 2.6 6. The dfa M in Jexercise2.6 accepts the string w = a. Modify M to create a new automaton M', so that L(M') = L(M) – {a}.
2.2 Surface Area: Multiplication Rule The surface area of the rectangle bounded by L and Wis In [] # YOUR CODE HERE In [ ]: Translate this equation into code and verify a few values of A with your calculator. Again, this code is simple a one-liner. raise Not ImplementedError() In [ ] # Print the area print("Area "1 = I A) A = L. W Next, we plot the histogram for A: plt.figure(figsize=(9,6)) # Define the figure size (the default is a little too small) plt.hist(A, np. arange (250,505,5), facecolor='darkblue', alpha=0.75) plt.xlabel('area (mm$^2$)') plt.ylabel('number of measurements per bin');
1. Write a program that prompts the user to enter the length from the center of a pentagon to a verte and computes the area of the pentagon, as shown in the following figure. 5 x s? The formula for computing the area of a pentagon is Area = (€) 4 x tan Where s is the length of a side. The side can be computed using the formula s = 2r sin where r is the length from the center of a pentagon to a vertex. Round up two digits after the decimal point.
PLEASE CODE IN PYTHON The Penny Pitch game is popular in amusement parks. Pennies are tossed onto a board that has certain areas marked with different prizes. For example: The prizes available on this board are puzzle, game, ball, poster, and doll. At the end of the game, if all of the squares that say BALL are covered by a penny, the player gets the ball. This is also true for the other prizes. The board is made up of 25 squares (5 x 5). Each prize appears on three randomly chosen squares so that 15 squares contain prizes.In Python, create a PennyPitch application that displays a Penny Pitch board (use [ and ] to indicate squares) with prizes randomly placed and then simulates ten pennies being randomly pitched onto the board. After the pennies have been pitched, the application should display a message indicating which prizes have been won, if any.
Python! Look at image thank you!
3.3.2: Nested loops: Print seats. Given numRows and numColumns, print a list of all seats in a theater. Rows are numbered, columns lettered, as in 1A or 3E. Print a space after each seat, including after the last. Use separate print statements to print the row and column. Ex: numRows = 2 and numColumns = 3 prints:1A 1B 1C 2A 2B 2C
Re-write Sample Program 11.2 so that it works for an array of structures. Write the program so that it compares 6 circles. You will need to come up with a new way of determining which circle’s center is closest to the origin. Sample code 11.2 #include <iostream>#include <cmath> // necessary for pow function#include <iomanip>using namespace std;struct circle // declares the structure circle{ // This structure has 6 membersfloat centerX; // x coordinate of centerfloat centerY; // y coordinate of centerfloat radius;float area;float circumference;float distance_from_origin;};const float PI = 3.14159;int main(){circle circ1, circ2; // defines 2 circle structure variablescout << "Please enter the radius of the first circle: ";cin >> circ1.radius;cout << endl<< "Please enter the x-coordinate of the center: ";cin >> circ1.centerX;cout << endl<< "Please enter the y-coordinate of the center: ";cin >>…
GRADED ACTIVITY #6.1 (M8.1): PART 1: REPETITION CONTROL STRUCTURE (FOR) Instruction: Create a flowchart and a java program that reads a positive, non-zero integer as input and checks if the integer is deficient, perfect, or abundant. A positive, non-zero integer, N, is said to be perfect if the sum of its positive proper divisors (i.e., the positive integers, other than Nitself, that divide N exactly) is equal to the number itself. If this sum is less than N, the number is said to be deficient. If the sum is greater than N, the number is said to be abundant. The first few perfect numbers are 6, 28, 496, and 8128. Illustrations: Number 6 28 For example, the number 6 is perfect, since 6 = 1 + 2+ 3, the number 8 is deficient, since 8 >1 + 2+ 4, while the number 12 is abundant, since 12 < 1 + 2+ 3+ 4 + 6. Factors of the number less than itself | Sum of Factors 3, 2, 1 |14, 7, 4, 2, 1 6 28 Sample Input/Output: Depicted below are sample outputs when the program is executed (the items in bold…