12.1.9 The differential cross section in a nuclear scattering experiment is given by do/dn = |ƒ(0)|². An approximate treatment leads to R exp[iko sin sin p]p dp do, where is an angle through which the scattered particle is scattered, and R is the nuclear radius. Show that f(0) = -ik 2π do dQ 2π = (π R²) 1 [J₁(kR sin 0) Л sin Ꮎ
12.1.9 The differential cross section in a nuclear scattering experiment is given by do/dn = |ƒ(0)|². An approximate treatment leads to R exp[iko sin sin p]p dp do, where is an angle through which the scattered particle is scattered, and R is the nuclear radius. Show that f(0) = -ik 2π do dQ 2π = (π R²) 1 [J₁(kR sin 0) Л sin Ꮎ
Related questions
Question
Please show complete solution clearly
![12.1.9 The differential cross section in a nuclear scattering experiment is
given by do/dn = |ƒ(0)|². An approximate treatment leads to
exp[iko sin sin p]p dp do,
where is an angle through which the scattered particle is scattered,
and R is the nuclear radius. Show that
R
f(0) = L. L
-ik 2π
2л
do
dΩ
[J₁(KR
= ( 7 R²) 1¹1(KR sin 6)
π
sin 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0c1f9eea-db8f-4542-94de-267de9ffa525%2F665dbf07-1199-4f5d-b566-081d67650447%2Fw2jdoc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:12.1.9 The differential cross section in a nuclear scattering experiment is
given by do/dn = |ƒ(0)|². An approximate treatment leads to
exp[iko sin sin p]p dp do,
where is an angle through which the scattered particle is scattered,
and R is the nuclear radius. Show that
R
f(0) = L. L
-ik 2π
2л
do
dΩ
[J₁(KR
= ( 7 R²) 1¹1(KR sin 6)
π
sin 0
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps with 2 images
