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12. What is the wavelength of the next standing wave (the next harmonic) of the pipe in the above problem? (2.67m) 4L (4)(z) ^ 2.67m 3

12. What is the wavelength of the next standing wave (the next harmonic) of the pipe in the above problem? (2.67m) 4L (4)(z) ^ 2.67m 3

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for question 12 why is the harmonic number 3 used in the equation instead of 2, as in question 11 the harmonic number is 1? this is a non graded practice worksheet
= .& + 2.5) (e) The student performing this experiment determines that the temperature of the room is actually slightly higher than 20 C. Is the calculation of the frequency in part (b) too high, too low, or still correct? T↑ VT Too high ✓Too low Still correct Justify your answer. Lower T => Lown I is to Low In exprimt 11. What is the fundamental frequency of the 2.00 meter closed pipe? (Assume the speed of sound is 340 m/s for this problem) Draw the standing wave. (42.5 Hz) (340) f-^ f=42.5 H₂ 1 (4) (2) 12. What is the wavelength of the next standing wave (the next harmonic) of the pipe in the above problem? (2.67m) (4)(z) 4L λ = 2.67m 3 SAMSUNG
Transcribed Image Text:= .& + 2.5) (e) The student performing this experiment determines that the temperature of the room is actually slightly higher than 20 C. Is the calculation of the frequency in part (b) too high, too low, or still correct? T↑ VT Too high ✓Too low Still correct Justify your answer. Lower T => Lown I is to Low In exprimt 11. What is the fundamental frequency of the 2.00 meter closed pipe? (Assume the speed of sound is 340 m/s for this problem) Draw the standing wave. (42.5 Hz) (340) f-^ f=42.5 H₂ 1 (4) (2) 12. What is the wavelength of the next standing wave (the next harmonic) of the pipe in the above problem? (2.67m) (4)(z) 4L λ = 2.67m 3 SAMSUNG
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