12. The hiker exerts a constant force of 135N on the sled at a 48.0o angle to the sled's displacement. At the same time, a constant 67.0N frictional force on the sled from the snow opposes the motion. Calculate the work done by the hiker, the work done by friction, and the net work done when the sled was pulled for a total 345m. Answer: The work done by the hiker and friction are respectively 3.12 and 1x10*J. The net work done is 8.04x10'J

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12
The hiker exerts a constant force of 135N on the sled
at a 48.0o angle to the sled's displacement. At the
same time, a constant 67.0N frictional force on the
sled from the snow opposes the motion. Calculate the
work done by the hiker, the work done by friction,
and the net work done when the sled was pulled for a total 345m.
Answer: The work done by the hiker and friction are respectively 3.12x10 J
and -2.31×10ʻJ. The net work done is 8.04×10°J.
Source: Nelson, Physics 12, 2009, p. 169, Tutorial 4
Transcribed Image Text:12 The hiker exerts a constant force of 135N on the sled at a 48.0o angle to the sled's displacement. At the same time, a constant 67.0N frictional force on the sled from the snow opposes the motion. Calculate the work done by the hiker, the work done by friction, and the net work done when the sled was pulled for a total 345m. Answer: The work done by the hiker and friction are respectively 3.12x10 J and -2.31×10ʻJ. The net work done is 8.04×10°J. Source: Nelson, Physics 12, 2009, p. 169, Tutorial 4
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