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12. Suppose that it is known that P(A/B) = 0.21, P(A) = 0.69, and P(AUB) = 0.13. (a) Find P(An B). Hint: Notice that P(B) is the sum of the probability of two shapes in your Venn diagram. (b) Find P(B). (c) Find P(AUB).maniw telord opbisden) sont dilidados besc

12. Suppose that it is known that P(A/B) = 0.21, P(A) = 0.69, and P(AUB) = 0.13. (a) Find P(An B). Hint: Notice that P(B) is the sum of the probability of two shapes in your Venn diagram. (b) Find P(B). (c) Find P(AUB).maniw telord opbisden) sont dilidados besc

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Please do question 12 and explain how you got the answer.
(b) Given that an athlete plays football or runs track, what is the probability that they are in 1st year? (c) Are the events "being in 2nd year" and playing football mutually exclusive? (d) If 1st year n Basketball contains 40 people, what was the sample size? 12. Suppose that it is known that P(A/B) = 0.21, P(A) = 0.69, and P(AUB) = 0.13. (a) Find P(An B). Hint: Notice that P(B) is the sum of the probability of two shapes in your Venn diagram. (b) Find P(B). (c) Find P(AUB). YoundExt121 13. Fifteen percent of all births involve Cesarean section. If a baby is born via natural birth they survive delivery with probability 0.98, whereas when a Cesarian section is performed the baby survives with probability 0.96.
Transcribed Image Text:(b) Given that an athlete plays football or runs track, what is the probability that they are in 1st year? (c) Are the events "being in 2nd year" and playing football mutually exclusive? (d) If 1st year n Basketball contains 40 people, what was the sample size? 12. Suppose that it is known that P(A/B) = 0.21, P(A) = 0.69, and P(AUB) = 0.13. (a) Find P(An B). Hint: Notice that P(B) is the sum of the probability of two shapes in your Venn diagram. (b) Find P(B). (c) Find P(AUB). YoundExt121 13. Fifteen percent of all births involve Cesarean section. If a baby is born via natural birth they survive delivery with probability 0.98, whereas when a Cesarian section is performed the baby survives with probability 0.96.
Expert Solution
Step 1

∪

∩

P(A|B) = 0.21

P(A')=0.69

P(A) = 1- P(A') = 0.31

 

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